Question

A 1.5 m wire carries a 9A current when a potential difference of 84 v is applied. what is the resistance of the wire

Answer 1

Ohm's law states that I=V/R (Current=volts divided by resistance). Since we're looking for resistance, we'll rewrite it as R=V/I. Then just plug in the numbers; R=84/9, R= 9 1/3 or 28/3. The resistance of the wire is 9.33... or 9 1/3 ohm's, depending on how you wanna write it.

Answer 2

Answer : The resistance of the wire is, 9.33 ohms

Solution : Given,

Electric current = 9 A

Potential difference = 84 V

Using ohm's law,

$V=I\times R$

or,

$R=\frac{V}{I}$

where,

R = resistance of wire

V = potential difference

I = electric current

Now put all the given values in the above formula, we get the resistance of the wire.

$R=\frac{84V}{9A}=9.33\Omega$

Therefore, the resistance of the wire is, 9.33 ohms