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VladimirAG [237]
3 years ago
7

CALL NOW $+1-855-241-6569$ aol mail not working on windows ## aol desktop gold email not working||USA||**2020*

Computers and Technology
1 answer:
LenKa [72]3 years ago
6 0

Answer:

extra 5 points lol

Explanation:

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Victoria is creating a brochure for her photography studio. She designed the layout and placed a photo in the center of the page
cestrela7 [59]

Assuming Victoria is using Adobe Photoshop to create her brochure, below are the steps she is required to follow.

She should first open the image on Photoshop, click on the image option and select duplicate just in case the resized image is not what she wants.

Still on the image option, she should select Image size. A screen will pop up at this point, indicating the image’s current size. For the purposes of image resizing, Victoria should select Pixel dimensions category.

She should be able to type her preferred dimensions for both the width and height. She should make sure ‘Constrain Proportions’ is unchecked to be able to type in separate values.

If she decides to use the photo editing program, she can simply click on the image, and if resize handles appear around it, she can click and drag those to the desired size.


3 0
3 years ago
Most languages allow a specialized selection structure called the ____ structure when there are several distinct possible values
aleksandr82 [10.1K]

Answer:

CASE

Explanation:

Case Structure is a mechanism that allows different executions when there are several distinct possible values for a single variable, and each value requires a different subsequent action depending on the value of the label.

Case structure is also a conditional control structure that appears in most modern programming languages and allows a selection to be made between several sets of program statements.

8 0
3 years ago
How to run angular project from github.
sergiy2304 [10]

Answer:

i have no ideaaaaaaaaaaaaaaaaaaaaaa

Explanation:

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6 0
2 years ago
Write a Java class to perform the following: 1. Write a method to search the following array using a linear search, ( target ele
Alina [70]

Answer:

Check the explanation

Explanation:

Linear search in JAVA:-

import java.util.Scanner;

class linearsearch

{

  public static void main(String args[])

  {

     int count, number, item, arr[];

     

     Scanner console = new Scanner(System.in);

     System.out.println("Enter numbers:");

     number = console.nextInt();

   

     arr = new int[number];

     System.out.println("Enter " + number + " ");

     

     for (count = 0; count < number; count++)

       arr[count] = console.nextInt();

     System.out.println("Enter search value:");

     item = console.nextInt();

     for (count = 0; count < number; count++)

     {

        if (arr[count] == item)

        {

          System.out.println(item+" present at "+(count+1));

         

          break;

        }

     }

     if (count == number)

       System.out.println(item + " doesn't found in array.");

  }

}

Kindly check the first attached image below for the code output.

Selection Sort in JAVA:-

public class selectionsort {

   public static void selectionsort(int[] array){

       for (int i = 0; i < array.length - 1; i++)

       {

           int ind = i;

           for (int j = i + 1; j < array.length; j++){

               if (array[j] < array[ind]){

                   ind = j;

               }

           }

           int smaller_number = array[ind];  

           array[ind] = array[i];

           array[i] = smaller_number;

       }

   }

     

   public static void main(String a[]){

       int[] arr = {9,94,4,2,43,18,32,12};

       System.out.println("Before Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

       System.out.println();

         

       selectionsort(arr);

       

       System.out.println("After Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

   }

}  

Kindly check the second attached image below for the code output.

Bubble Sort in JAVA:-

public class bubblesort {

   static void bubblesort(int[] array) {

       int num = array.length;

       int temp = 0;

        for(int i=0; i < num; i++){

                for(int j=1; j < (num-i); j++){

                         if(array[j-1] > array[j]){

                           

                                temp = array[j-1];

                                array[j-1] = array[j];

                                array[j] = temp;

                        }

                         

                }

        }

   }

   public static void main(String[] args) {

               int arr1[] ={3333,60,25,32,55,620,85};

               

               System.out.println("Before Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

               System.out.println();

                 

               bubblesort(arr1);

               

               System.out.println("After Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

 

       }

}  

Kindly check the third attached image below for the code output.

Binary search in JAVA:-

public class binarysearch {

  public int binarySearch(int[] array, int x) {

     return binarySearch(array, x, 0, array.length - 1);

  }

  private int binarySearch(int[ ] arr, int x,

        int lw, int hg) {

     if (lw > hg) return -1;

     int middle = (lw + hg)/2;

     if (arr[middle] == x) return middle;

     else if (arr[middle] < x)

        return binarySearch(arr, x, middle+1, hg);

     else

        return binarySearch(arr, x, lw, middle-1);

  }

  public static void main(String[] args) {

     binarysearch obj = new binarysearch();

     int[] ar =

       { 22, 18,12,14,36,59,74,98,41,23,

        34,50,45,49,31,53,74,56,57,80,

        61,68,37,12,58,79,904,56,99};

     for (int i = 0; i < ar.length; i++)

        System.out.print(obj.binarySearch(ar,

           ar[i]) + " ");

     System.out.println();

     System.out.print(obj.binarySearch(ar,19) +" ");

     System.out.print(obj.binarySearch(ar,25)+" ");

     System.out.print(obj.binarySearch(ar,82)+" ");

     System.out.print(obj.binarySearch(ar,19)+" ");

     System.out.println();

  }

}

Kindly check the fourth attached image below for the code output

7 0
3 years ago
Write a program that asks the user to enter the amount that he or she has budgeted for a month. A loop should then prompt the us
Dominik [7]

Answer:

import java.util.*;

public class Main {

public static void main(String[] args)

{

Scanner scan = new Scanner();

double budget=0, num=0, total=0;

System.out.println("Your budget for the month? ");

budget=scan.nextDouble();

System.out.println("enter all expense, and after that type -9999 to quit: ");

while(num != -9999)

{

total+=num;

num=scan.nextDouble();

}

if(total<=budget)

{

System.out.println("under budget by ");

System.out.println(budget-total);

}

else

{

System.out.println("over budget by ");

System.out.println(total-budget);

}

}

}

Explanation:

  • Take the budget as an input from user and store it to the budget variable.
  • Loop until user has entered all his expenses and keep on adding them to the total variable.
  • Check If the total is less than or equal to budget or otherwise, and then print the relevant message accordingly.
4 0
3 years ago
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