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SpyIntel [72]
3 years ago
14

Flowchart is written using english language.true or false​

Computers and Technology
2 answers:
DedPeter [7]3 years ago
7 0

the answer is true hope it helps

Ira Lisetskai [31]3 years ago
3 0
Answer is true I believe
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3. When code tracing, why is it important to iteratively test parts of the program?
GenaCL600 [577]

Answer:

A. To isolate errors in the outcomes of code.

<em>Hope this helps! ^-^</em>

<em>-Isa</em>

7 0
3 years ago
Write a program that reads the contents of the two files into two separate lists. The user should be able to enter a boy’s name,
insens350 [35]

Answer:

Check Explanation.

Explanation:

A programming language is used by engineers, technologists, scientists or someone that learnt about programming languages and they use these programming languages to give instructions to a system. There are many types for instance, c++, python, Java and many more.

So, the solution to the question above is given below;

#define the lists

boyNames=[]

girlNames=[]

#open the text file BoyNames.txt

with open('BoyNames.txt','r') as rd_b_fl:

boyNames=rd_b_fl.readlines()

boyNames=[name.strip().lower() for name in boyNames]

#open the text file GirlNames.txt

with open('GirlNames.txt','r') as rd_b_fl:

girlNames=rd_b_fl.readlines()

girlNames=[name.strip().lower() for name in girlNames]

#print the message to prompt for name

print('Enter a name to see if it is a popular girls or boys name.')

while True:

#prompt and read the name

name=input('\nEnter a name to check, or \"stop\" to stop: ').lower()

# if the input is stop, then exit from the program

if name=='stop':

break

# If the girl name exits in the file,then return 1

g_count=girlNames.count(name)

# if return value greater than 0, then print message

if g_count>0:

print(name.title()+" is a popular girls name and is ranked "

+str(girlNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular girls name")

## If the boy name exits in the file,then return 1

b_count=boyNames.count(name)

if b_count>0:

print(name.title()+" is a popular boys name and is ranked "

+str(boyNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular boys name")

3 0
3 years ago
Which bug type would you suggest for the following bug? The button label "Add to cart" is not fully visible.
harina [27]
Butterfly one I forgot the name metapods evolution
3 0
3 years ago
What is the shortcut key to apply /remove the subscript effect?<br> Ctrl+=<br><br> Ctrl-+
telo118 [61]

Answer:

Press "Ctrl, "Shift" and "=" on your keyboard to turn off superscript formatting.

5 0
3 years ago
How to calculate a pid controller
pishuonlain [190]

Answer:

Control by PID1

is a control method often used for servos.

Don't you know what a bondage is? Well, it's a system, capable of reaching and

maintain a setpoint thanks to the measurements it performs.

Imagine, for example, in a car on the highway. You want to drive at 130Km / h

without having to press the accelerator. Your car's cruise control should

by itself maintain this speed. When approaching a slope the system "notices" that for

the same power at the level of the motor, it no longer reaches the 130 km / h setpoint and will add a

little acceleration. Yes but by how much? And how long will it take for the system to

stabilize around the setpoint?

That's the whole servo problem and PID control is one way to solve it!

PID is the most widely used regulator in industry. The idea of ​​this control body is to

intentionally modify the value of the error which remains between the setpoint and the measurement

performed.

For example in the case of a position control the error would be: ε = c (p) - s (p)

In the case of proportional control, the error is virtually amplified by a certain gain

constant that should be determined according to the system.

Setpoint (t) = Kp.ε (t)

What in Laplace gives:

Setpoint (p) = Kp.ε (p)

Explanation:

5 0
3 years ago
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