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alexandr402 [8]
3 years ago
10

Someone please help with the picture shown!!

Mathematics
2 answers:
serg [7]3 years ago
5 0

Answer:

its between 45 and thirty I think its 45

Step-by-step explanation:

I did a similar problem.

alexira [117]3 years ago
4 0

Answer:

C

Step-by-step explanation:

hehe :D

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,..............,...............?..?.?.?.?.................
Alecsey [184]

Answer:

,..............,...............?..?.?.?.?.................

Step-by-step explanation:

7 0
3 years ago
Perform the indicated operation g(x)=-x-3 h(x) = x 2+X Find (goh) (x)​
Klio2033 [76]

Answer:

(g\circ h)(x)=-x^2-x-3

Step-by-step explanation:

So we have the two functions:

g(x)=-x-3\text{ and } h(x)=x^2+x

And we want to find:

(g\circ h)(x)

This is the same thing as:

=g(h(x))

So, substitute h(x) into g(x):

g(x)=-x-3\\g(h(x))=-(x^2+x)-3

Distribute the negative:

g(h(x))=-x^2-x-3

And we're done!

So:

(g\circ h)(x)=-x^2-x-3

6 0
3 years ago
Read 2 more answers
Please help me branniest
Goshia [24]

Answer:

the answer is C

Step-by-step explanation:


7 0
3 years ago
Question is in the picture:
Sholpan [36]
Its 5 times larger.
3 0
3 years ago
Write the relation as a set of on rdered pai
kirill115 [55]

The relation as a set of ordered pairs is d. {(–2, 1), (0, -1), (2, -3)}.

Step-by-step explanation:

Step 1:

First, we plot the three points on the given graph.

The coordinates are given in the following form (x coordinate, y coordinate) where the symbol of the coordinates depends on the quadrant on which the point lies.

For the first quadrant, both x and y values are positive.

For the second quadrant, the x value is negative but the y value is positive.

For the third quadrant, both the values of x and y are negative.

For the fourth quadrant, the x value is positive but the y value is negative.

Step 2:

The first point has an x value of 2 and a y value of 1 since it is in the second quadrant, the coordinates are (-2, 1).

The second point has an x value of 0 and a y value of 1 since it is in the third or fourth quadrant, the coordinates are (0, -1).

The third point has an x value of 2 and a y value of 3 since it is in the fourth quadrant, the coordinates are (2, -3).

So the coordinates are {(–2, 1), (0, -1), (2, -3)} which is option d.

6 0
3 years ago
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