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3 years ago

7

Kaitlin's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Kaitlin $5.50 per pound, and t

ype B coffee costs $4.25 per
pound. This month's blend used twice as many pounds of type B coffee as type A, for a total cost of $448.00. How many pounds of type A coffee were used?

1 answer:

viktelen [127]3 years ago

3 0

Answer:

The quantity of Type A coffee were used is 32 pounds .

Step-by-step explanation:

Given as :

The cost of type A coffee = $ 5.50 per pound

The cost of type b coffee = $ 4.25 per pound

The total cost of coffee = $ 448.00

The quantity of coffee of type B is twice than type A

Let The quantity of type A coffee = x pound

So, The quantity of type B coffee = 2 × x pound

Now, According to question

x × $ 5.50 + 2 x × $ 4.25 = $ 448

Or, x × $ 5.50 + x × $ 8.5 = $ 448

Or, 14 x = 448

∴ x = $\frac{448}{14}$

I.e x = 32

∴ The quantity of type A coffee = 32 pound

And, The quantity of type B coffee = 2 × 32 = 64 pound

Hence The quantity of Type A coffee were used is 32 pounds . Answer

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A random sample of adults were asked whether they prefer reading an e-book over a printed book. The survey resulted in a sample

djyliett [7]

Answer: $(0.10\ ,\ 0.18)$

Step-by-step explanation:

According to the empirical rule, the 95% confidence interval for the true population proportion is given by :-

$(p'-2\sigma_{p'}\ ,\ p'+2\sigma_{p'})$

Given : . The survey resulted in a sample proportion of p′=0.14, with a sampling standard deviation of σp′=0.02, who preferred reading an e-book.

Then, the 95% confidence interval for the true proportion of adults who prefer e-books will be :-

$(0.14-2(0.02)\ ,\ 0.14+2(0.02))\\\\=(0.14-0.04\ ,\ 0.14+0.04)\\\\=(0.10\ ,\ 0.18)$

Hence, the 95% confidence interval for the true proportion of adults who prefer e-books= $(0.10\ ,\ 0.18)$

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3 years ago

Suppose f (x) = x^2. Find the graph of f(x+2)

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$\bf ~~~~~~~~~~~~\textit{function transformations}
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~~~~y={{ A}}({{ B}}x+{{ C}})+{{ D}}
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f(x)={{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
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f(x)={{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
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f(x)={{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
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$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
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~~~~~~\textit{reflection over the x-axis}
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\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
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$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
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with that template in mind,

$\bf f(x)=x^2\qquad \quad f(x+2)=(x+2)^2\implies f(x+2)=\stackrel{A}{1}(\stackrel{B}{1}x\stackrel{C}{+2})^2\stackrel{D}{+0}$

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3 years ago

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

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Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

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Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

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Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

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Norma-Jean [14]

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Hello, I asked help for this problem several times to no answer. I dont understand it and can use any help. Please, and thank yo

Oduvanchick [21]

Check the picture below.

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