well, we're assuming all along that Merina owes Bradford $2000, because in the 1st scenario, she was going to pay twice $1000.
on the 2nd scenario, she'll be paying the same $2000 but split 7 months from now and then 7 months later, same 2000 bucks, at which point Bradford applied 8.5% interest.
using those assumptions, since the wording is not quite clear, we can say that Merina is simply paying 2000 bucks plus the 8.5%
![\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{8.5\% of 2000}}{\left( \cfrac{8.5}{100} \right)2000}\implies 170 \\\\[-0.35em] ~\dotfill\\\\ \cfrac{\stackrel{principal}{2000}~~ + ~~\stackrel{interest}{170}}{2}\implies \stackrel{\textit{two equal payments of}}{1085}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Ba%5C%25%20of%20b%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20%5Cleft%28%20%5Ccfrac%7Ba%7D%7B100%7D%20%5Cright%29%5Ccdot%20b%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D~%5Chspace%7B5em%7D%5Cstackrel%7B%5Ctextit%7B8.5%5C%25%20of%202000%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B8.5%7D%7B100%7D%20%5Cright%292000%7D%5Cimplies%20170%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B%5Cstackrel%7Bprincipal%7D%7B2000%7D~~%20%2B%20~~%5Cstackrel%7Binterest%7D%7B170%7D%7D%7B2%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Btwo%20equal%20payments%20of%7D%7D%7B1085%7D)
Answer:
the correct answers are 22 and 8
4.5 boxes of nails are required for finishing 2 tables
Step-by-step explanation:
Given:
3.4 boxes of nails are required for finishing 1.5 tables
Required:
How much boxes of nails would he use for finishing 2 tables
Solution:
We can solve using Unitary Method:
Nails needed to finish 1.5 tables = 3.4 boxes
Nails needed to finish 1 table = 
Nails needed to finish 2 tables = 
So, 4.5 boxes of nails are required for finishing 2 tables.
Keywords: Word Problems
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You have to complete the square to get it into vertex form. Do this by setting the function equal to zero and at the same time moving the constant over to the other side of the equals sign so you have this:

. Now we can complete the square on the polynomial by taking half the linear term, squaring it, and adding it to both sides. Our linear term is 4. Half of 4 is 2, and 2 squared is 4, so we add 4 to both sides:

and simplify to get

. In this process we have created a perfect square binomial on the left, which happens to be

. Now move the -6 back over by addition to get

. The vertex is found at (-2, 6), the third choice down.
Step-by-step explanation:



Equating,




Placing it,


