When you have a linear equation of the form y = mx, such as this one, you know immediately that the line passes thru the origin (0,0). Were the form y = mx + b, then the y-intercept would be (0,b) and the x-intercept ( [-b/m, 0).
Answer:
A a pair of intersecting lines
Step-by-step explanation:
i got it right on the test bub
The type and number of solutions is (b) two imaginary solutions.
<h3>How to determine the type and number of solutions?</h3>
The equation is given as:
3x² + 5x + 5 = 0
A quadratic equation can be represented as:
ax^2 + bx + c = 0
Where, the discriminant (d) is
d = b^2 - 4ac
So, we have
d = 5^2 - 4 * 3 * 5
Evaluate
d = -35
The value of d is negative
This means that the equation has only imaginary solutions
Hence, the type and number of solutions is (b) two imaginary solutions.
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Answer:
y = - 
x - 1
Step-by-step explanation:
Assuming you require the equation of the line
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - , then
y = - x + c ← is the partial equation
To find c substitute (12, - 4) into the partial equation
- 4 = - 3 + c ⇒ c = - 4 + 3 = - 1
y = - x - 1 ← equation of line
The Answer is...................
<span>B. Negative</span>
