Question

A gas in a sealed container has a pressure of 125 atm at a temperature of 303 K. If the pressure in the container is increased to 200 atm, what is the new temperature if the volume remains constant?
(Show work pls :)!)

Answer 1

Answer:

485 K

Explanation:

Step 1: Given data

• Initial pressure (P₁): 125 atm

• Initial temperature (T₁): 303 K

• Final pressure (P₂): 200 atm

• Final temperature (T₂): ?

Step 2: Calculate the final temperature of the gas

Assuming constant volume and ideal behavior, we can calculate the final temperature of the gas using Gay Lussac's law.

P₁/T₁ = P₂/T₂

T₂ = P₂ × T₁/P₁

T₂ = 200 atm × 303 K/125 atm = 485 K