The vertex of f(x) = 3x^2 + 12x − 8 is (2,28) absolute minimum
<h3>How to determine the vertex?</h3>
The equation is given as:
f(x) = 3x^2 + 12x − 8
Differentiate the function
f'(x) = 6x + 12
Set to 0
6x + 12 = 0
Divide through by 6
x + 2 = 0
Solve for x
x = -2
Substitute x = -2 in f(x) = 3x^2 + 12x − 8
f(2) = 3 *2^2 + 12 *2 − 8
Evaluate
f(2) = 28
This means that the vertex is (2,28)
A quadratic function is represented as:
f(x) =ax^2 + bx + c
When a is positive, then the vertex of the function is an absolute minimum.
This means that f(x) = 3x^2 + 12x − 8 has an absolute minimum vertex because 3 is positive
Read more about quadratic functions at:
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Answer:
x=2
Step-by-step explanation:
4x=8
/4 /4
divide both sides by 4
x=2
Answer:
x = 15
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
x² + 20² = 25²
x² + 400 = 625 ( subtract 400 from both sides )
x² = 225 ( take the square root of both sides )
x =
= 15
Answer:
a) 0.7063; b) 0.0228; c) 0.2709
Step-by-step explanation:
We use z scores for these problems. The formula for a z sore is

For part a,
We want P(5 ≤ X ≤ 11):
z = (5-9.6)/2.3 = -4.6/2.3 = -2
z = (11-9.6)/2.3 = 1.4/2.3 = 0.61
The area under the curve to the left of z = -2 is 0.0228. The area under the curve to the left of z = 0.61 is 0.7291. This makes the area between them
0.7291 - 0.0228 = 0.7063
For part b,
We want P(X ≤ 5):
z = (5-9.6)/2.3 = -4.6/2.3 = -2
The area under the curve to the left of z = -2 is 0.0228.
For part c,
We want P(X > 11):
z = (11-9.6)/2.3 = 1.4/2.3 = 0.61
The area under the curve to the left of z = 0.61 is 0.7291. However, we want the area to the right; this means we subtract from 1:
1-0.7291 = 0.2709