Answer:
The rate of change of the distance between the cars at that instant is 5.46 meters per second
Step-by-step explanation:
Speed of first car = 7 m/s
Speed of second car = 3 m/s
At instant, distance of first car from intersection = 5 meters
distance of second car from intersection = 12 meters
Therefore, we have
Distance between both cars at intant = √(12² + 5²) = 13 m
Rate of cahnge of distance is given by;
2ddd/dt = d(x² + y²)/dt = 2xdx/dt + 2ydy/dt
= 26dd/dt = 2×5×7 + 2×12×3 = 142
dd/dt = 142/26 = 5.46 m/s.
That is the rate of change of the distance between the cars at that instant = 5.46 meters per second.
Step-by-step explanation:
step 1. x + 4.75 - 6.55 = 5.43
step 2. looks like b is the only answer.
Answer:
256.56ft³
Step-by-step explanation:
V₍cone₎= πr²(h/3)
=π×(7)²×(5/3)
=(3.14)×(49)×(1.67)
=256.4ft³
Y=mx+b x=slope b=y intercept
