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vodka [1.7K]
3 years ago
6

PLEASE HELP! i have by the end of the day to turn this in. PLEASE DONT GUESS

Mathematics
2 answers:
SVEN [57.7K]3 years ago
6 0

Answer:

122

Step-by-step explanation:

x = 180-(180-50-72) = 180-(130 - 72) = 180 - 130 + 72 = 50 + 72 = 122

Anit [1.1K]3 years ago
6 0

add 50+72 and it will give you 122 and the triangle should be uhhh hang on gosh this is hard to remember, um 180 I believe so if you do 180-122 it will give you 58. Now you do 180 -58 because of the °180 line and I believe and it will give you 122 for the missing x but don't take my word on it cause I'm not sure if it's right but that's what I remember

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Answer:

a) n=\frac{0.76(1-0.76)}{(\frac{0.01}{1.64})^2}=4905.83  

And rounded up we have that n=4906

b) For this case since we don't have prior info we need to use as estimatro for the proportion \hat p =0.5

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And rounded up we have that n=6724

Step-by-step explanation:

We need to remember that the confidence interval for the true proportion is given by :  

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Part a

The estimated proportion for this case is \hat p =0.76

Our interval is at 90% of confidence, and the significance level is given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. The critical values for this case are:

z_{\alpha/2}=-1.64, t_{1-\alpha/2}=1.64

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

The margin of error desired is given ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Replacing we got:

n=\frac{0.76(1-0.76)}{(\frac{0.01}{1.64})^2}=4905.83  

And rounded up we have that n=4906

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For this case since we don't have prior info we need to use as estimatro for the proportion \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.01}{1.64})^2}=6724  

And rounded up we have that n=6724

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