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3 years ago

PLEASE HELP! i have by the end of the day to turn this in. PLEASE DONT GUESS

Mathematics

2 answers:

SVEN [57.7K]3 years ago

6 0

Answer:

122

Step-by-step explanation:

x = 180-(180-50-72) = 180-(130 - 72) = 180 - 130 + 72 = 50 + 72 = 122

Anit [1.1K]3 years ago

6 0

add 50+72 and it will give you 122 and the triangle should be uhhh hang on gosh this is hard to remember, um 180 I believe so if you do 180-122 it will give you 58. Now you do 180 -58 because of the °180 line and I believe and it will give you 122 for the missing x but don't take my word on it cause I'm not sure if it's right but that's what I remember

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Harman [31]

Answer:

(a)Revenue function, $R(x)=580x-x^2$

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit, $P(x)=-35x^2+280x-900$

(d)x=4

Step-by-step explanation:

Part A

Price Function $= 580 - 10x$

The revenue function

$R(x)=x\cdot (580-10x)\\R(x)=580x-x^2$

The marginal revenue function

$\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x$

Part B

(Fixed Cost)

The total cost function of the company is given by $c=(30+5x)^2$

We expand the expression

$(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2$

Therefore, the fixed cost is 900 .

Marginal Cost Function

If $c=900+300x+25x^2$

Marginal Cost Function, $\frac{dc}{dx}= (900+300x+25x^2)'=300+50x$

Part C

Profit Function

Profit=Revenue -Total cost

$580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900$

Part D

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

$P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4$

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3 years ago

What is the same as 3(4 + 5 + 6)?

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Answer:

Step-by-step explanation:

3(4 + 5 + 6)

= 3(15)

= 3 × 15

= 45 (Ans)

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3 years ago

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allsm [11]

Put them in order from smallest to largest
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answer
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3 years ago

Read 2 more answers

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Answer:

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Step-by-step explanation:

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