At what value of x do the graphs of the equations below intersect?

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

4 0

Answer:

They intersect at an x value of 2

Step-by-step explanation:

Rewrite the equations into slope y-int form:

-2x + y = -6

y = 2x - 6

x + 2y = -2

2y = -2 - x

y = -1/2x - 1

Next, set the two equations as equal and solve for x:

2x - 6 = -1/2x - 1

2x + 1/2x = -1 + 6

4x + x = -2 + 12

5x = 10

x = 2

You might be interested in

What value of x would result in the numerical value of zero in the expression?

mash [69]

Answer:

HINDI KO ALAM WAHAHAHAHAHAHAHA

4 0

3 years ago

Please help me on this

Citrus2011 [14]

B is the answer i say .

5 0

3 years ago

Write in standard form the equation of a line with a slope of -3/5 and a y intercept of -3

Vlada [557]

Answer:

5y+3x=-9

Step-by-step explanation:

Let us start by the general form of the standard equation, Ax+By=C. One way we can solve this problem is by finding the slope-intercept form of this equation, y=mx+b, and converting it into the standard equation. In the slope-intercept form, m represents the slope, b represents the y intercept.

From this problem, we are given both the slope and the y intercept. We know have the equation:

$y=-\frac{3}{5}x -3$

Great! Now let us rearrange the terms so that the y and x terms are on one side of the equation.

$y+\frac{3}{5} x=-3$

This seems right, but a standard equation must have coefficient values that are real numbers. So, A and B must be real numbers. We can do this by multiplying the entire equation by 5 and ridding the denominator of the A term.

$5y+3x=-9$