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Anna [14]
3 years ago
9

Find the values of x and y.​

Mathematics
1 answer:
olchik [2.2K]3 years ago
8 0

Answer:

value of x = 26

value of y = 26 \|2

( 26 root 2 )

Step-by-step explanation:

here's the solution : -

=》

\sin(45)  =   \frac{perpendicular}{hypotenuse}

=》

\frac{1}{ \sqrt{2} }  =  \frac{26}{y}

=》

y = 26 \sqrt{2}

and

\tan(45)  =  \frac{perpendicular}{base}

=》

1 =  \frac{26}{x}

=》

x = 26

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Step-by-step explanation:

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Given:
notsponge [240]

A line <u>bisector</u> is a <em>straight </em>line that <u>divides</u> a given line into two equal parts. Thus the following steps are required by Naomi to show that point D is <em>equidistant</em> from points  A and C.

BD ⊥ AC (given)

BD = 3 units, and AC = 8 units.

BD is the <em>perpendicular</em> bisector of <u>segment</u> AC (given)

Thus,

<BDA  ≅ <BDC <em>(right</em> angles formed by a <u>perpendicular</u> bisector)

AD ≅ DC <em>(equal</em> parts of a<em> bisected l</em>ine)

AD ≅ DC = 4 units

Thus joining <u>points</u> B to A, and B to C,

BA ≅ BC.

So that applying <em>Pythagoras</em> theorem to ΔABD, we have:

/hyp/^{2} = Adj 1^{2} + Adj 2^{2}

AB^{2} = 3^{2} + 4^{2}

       = \sqrt{25}

 AB      = 5 units

So that,

BA ≅ BC = 5 units

Therefore, it can be <u>concluded</u> that point D is <em>equidistant</em> from points A and C.

For more clarifications on a perpendicular bisector of a line, visit: brainly.com/question/929137

#SPJ1

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