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3 years ago

Name the maximum and minimum of the function

Mathematics

1 answer:

stiv31 [10]3 years ago

8 0

The alimentary canal and the <span>gastrointestinal tract (GI tract)</span>

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Triangle BDC is isosceles

Ganezh [65]

ZCAB angle is congruent to ZBAD

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2 years ago

?????????????????????????????

sergeinik [125]

Answer:

B. 3

Step-by-step explanation:

If you were to multiply the top equation by 3 then the x value for the first equation would be 6 and since the bottom equation's x value is -6, if you were to add them, they would cancel eachother off.

LOL hope this makes sense :) Please give brainliest!! Thanks!!

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3 years ago

Can anyone help me with this please I need help

Gnoma [55]

Answer:

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2 years ago

elizabeth and her sister each go to the store to buy a piece of pizza for $1.25 and a soda for $0.85 each. How much do they spen

Radda [10]

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$12.50

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3 years ago

Use the arc length formula to find the length of the curve y = 2 − x2 , 0 ≤ x ≤ 1. Check your answer by noting that the curve is

Lina20 [59]

By using the arc length formula, we will see that the length of the curve is L = 1.48

<h3>How to use the arc length formula?</h3>

Here we have the curve:

y = 2 - x^2 with 0 ≤ x ≤ 1

And we want to find the length of the curve.

The arc length formula for a curve y in the interval [x₁, x₂] is given by:

$L =\int\limits^{x_2}_{x_1} {\sqrt{1 + \frac{dy}{dx}^2} } } \, dx$

For our curve, we have:

dy/dx = -2x

And the interval is [0, 1]

Replacing that we get:

$L =\int\limits^{1}_{0} {\sqrt{1 + (-2x)^2} } } \, dx\\\\L \int\limits^{1}_{0} {\sqrt{1 + 4x^2} } } \, dx\\$

This integral is not trivial, using a table you can see that this is equal to:

$L = (\frac{Arsinh(2x)}{4} + \frac{x*\sqrt{4x^2 + 1} }{2})$

evaluated from x = 1 to x = 0, when we do that, we will get:

$L = \frac{Arsinh(2) + 2*\sqrt{5} }{4} = 1.48$

That is the length of the curve.

If you want to learn more about curve length, you can read:

brainly.com/question/2005046

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2 years ago