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irga5000 [103]
3 years ago
8

Can someone please explain AAS SAS SSS ASA CPCTC

Mathematics
1 answer:
Lostsunrise [7]3 years ago
6 0

The Angle Angle Side postulate (often abbreviated as AAS) states that if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then these two triangles are congruent.

The Side Angle Side postulate (often abbreviated as SAS) states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent.

SSS stands for "side, side, side" and means that we have two triangles with all three sides equal. For example: is congruent to: (See Solving SSS Triangles to find out more) If three sides of one triangle are equal to three sides of another triangle, the triangles are congruent.

ASA stands for "angle, side, angle" and means that we have two triangles where we know two angles and the included side are equal. If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.

CPCTC is an acronym for corresponding parts of congruent triangles are congruent. CPCTC is commonly used at or near the end of a proof which asks the student to show that two angles or two sides are congruent. ... Corresponding means they're in the same position in the 2 triangles.

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Natasha_Volkova [10]
<span> </span>

You can use (a+b)2 = a2+2ab+b2.
(2x - 3)2 = (2x)2 + 2(2x)(-3) + (-3)2 = 4x2 - 12x + 9

Or you can use FOIL.

(2x - 3)2 = (2x - 3)(2x - 3) = (2x)2 + (2x)(-3) + (-3)(2x) + (-3)2 = 4x2 - 12x + 9



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Each bar weighs 2 oz

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3 years ago
Jay wants to make a box, with no lid (or top), out of a 10" x 6" rectangular piece of cardboard. If Jay cuts squares with dimens
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Answer:

a.V(x)=x(10-2x)(6-2x)

b.S(x)=4(15-x^2)

Step-by-step explanation:

Dimensions of rectangular piece of cardboard=10\times 6

According to question

Length of box,l=10-2x

Breadth of box,b=6-2x

Height of box,h=x

a.

Volume of box=l\times b\times h

Substitute the values in the formula

Volume of box=x(10-2x)(6-2x)

V(x)=x(10-2x)(6-2x)

b.Surface area of box=2(b+l)h+lb

Because the box has no lid

Substitute the values in the formula

Surface area of box=2(10-2x+6-2x)x+(10-2x)(6-2x)

Surface area of box=2(16-4x)x+60-20x-12x+4x^2

Surface area of box=32x-8x^2+60-32x+4x^2

Surface area of box=60-4x^2=4(15-x^2)

Surface area of box, S(x)=4(15-x^2)

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