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3 years ago

Simplify 8d-6e - 3d + 4e.

Mathematics

2 answers:

Anastasy [175]3 years ago

5 0

Answer:

5d-2e

Step-by-step explanation:

olga nikolaevna [1]3 years ago

5 0

Answer:5d - 2e

Step-by-step explanation:

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the Johnsons want to cover their backyard with new grass their backyard is rectangular with a length of 3x - 2 feet and a width

Andre45 [30]

<h2>Hello!</h2>

The answer is:

The area that the want to cover with new grass will be:

$Area_{grass}=8x^{2} -12x-22$

If we want to calculate what is the ara of the region of the backyard that they want to cover with new grass, we need to calculate the area of the backyard, calculate the area of the swimming pool and its patio, and the last step is to subtract the area of the swimming pool and its patio to the total area of the backyard.

So, to calculate the areas, we need to use the following formula:

$Area=Length*Width$

Also, we need to remember how the distributive property works, since we are going to need it.

We have that:

$(a+b)(c+d)=ac+ad+bc+bd$

We are given the following information:

For the backyard we have:

$Length=3x-2\\Width=3x+1$

For the swimming pool and its patio:

Since there it's not mentioned, let be the first expression the length, and the second one, the width.

$Length=x+4\\Width=x+5$

Then, calculating we have:

Backyard:

$Area_{backyard}=(3x-2)*(3x+1)=9x^{2}+3x-6x-2=9x^{2}-3x-2$

Swimming pool and patio:

$Area_{swimmingpool}=(x+4)*(x+5)=x^{2}+5x+4x+20=x^{2}+9x+20$

Now, calculating the area that they want to cover with new grass, we have:

$Area_{grass}=Area_{backyard}-Area_{swimmingPool}\\\\Area_{grass}=(9x^{2}-3x-2)-(x^{2}+9x+20)\\\\Area_{grass}=9x^{2} -x^{2} -3x-9x-2-20\\\\Area_{grass}=8x^{2} -12x-22$

Hence, we have that the area that the want to cover with new grass will be:

$Area_{grass}=8x^{2} -12x-22$

Have a nice day!

3 0

3 years ago

What is the slope of the line through (-1,4) and (5,2)

butalik [34]

Answer:

Slope (m) = $-\frac{1}{3}$

Step-by-step explanation:

Use the following equation:

Slope $(m) = \frac{y_2 - y_1}{x_2 - x_1}$

Let:

$(x_1 , y_1) = (-1 , 4)\\(x_2 , y_2) = (5 , 2)$

Plug in the corresponding numbers to the corresponding variables:

$m = \frac{2 - 4}{5 - (-1)} = \frac{2 - 4}{5 + 1} = \frac{-2}{6}$

Simplify. Divide common factors from both the numerator and denominator:

$\frac{(-\frac{2}{6})}{\frac{2}{2} } = -\frac{1}{3}$

$-\frac{1}{3}$ is your answer.

8 0

3 years ago

Which relation Is a function? From the graphs

kicyunya [14]

Answer:

3rd one

Step-by-step explanation:

because it's close

5 0

4 years ago

Read 2 more answers

Maria bought seven boxes a week later half of all her boxes were destroyed in a fire there are now only 22 boxes that with how m

hodyreva [135]

Maria started off with 44 boxes.

6 0

3 years ago

In the Brady's Family, each girl has twice as many brothers as she has sisters.

levacccp [35]

Answer:

3 girls and 4 boys

Step-by-step explanation:

Writing the number of girls in the family as g and the number of boys in the family as b,

we know that each girl has twice as many brothers as sisters. Therefore, the amount of boys in the family (b, or how many brothers each girl has) is twice the number of the amount of girls in the family (g) minus 1 (g-1) (subtract 1 because each girl's number of sisters does not include the girl herself). We can write this as

b = 2(g-1)

Next,

we know that each boy has the same amount of brothers as sisters. Therefore, the amount of boys in the family minus 1 (b-1, subtracting 1 because we don't include the boy that has the brothers) is equal to the amount of girls in the family (g). we can write this as

b-1 = g

Therefore, we have

b = 2(g-1)

b-1 = g

Plugging b-1 = g into the first equation, we get

b = 2 (g-1)

2(g-1) = 2((b-1) - 1) = b

= 2(b-1-1)

= 2(b-2)

= 2b-4

b = 2b-4

subtract 2b from both sides to make it so that only b values and their coefficients are on one side

-b = -4

multiply both sides by -1 to solve for b

b=4

Therefore, there are 4 boys in the family and b-1 = 4-1 = 3 girls in the family.

3 0

3 years ago