Given that Jon said,
"m-1 is always greater than 1-m"
we want to find how true the statement is;
![\begin{gathered} \text{for m = positive integer.} \\ m=5 \\ m-1=5-1=4 \\ 1-m=1-5=-4 \\ So,\text{ } \\ m-1>1-m \\ \text{for m equals positive integer } \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7Bfor%20m%20%3D%20positive%20integer.%7D%20%5C%5C%20m%3D5%20%5C%5C%20m-1%3D5-1%3D4%20%5C%5C%201-m%3D1-5%3D-4%20%5C%5C%20So%2C%5Ctext%7B%20%7D%20%5C%5C%20m-1%3E1-m%20%5C%5C%20%5Ctext%7Bfor%20m%20equals%20positive%20integer%20%7D%20%5Cend%7Bgathered%7D)
secondly for negative values of m;
![\begin{gathered} m=-5 \\ m-1=-5-1=-6 \\ 1-m=1-(-5)=1+5=6 \\ So, \\ m-1](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20m%3D-5%20%5C%5C%20m-1%3D-5-1%3D-6%20%5C%5C%201-m%3D1-%28-5%29%3D1%2B5%3D6%20%5C%5C%20So%2C%20%5C%5C%20m-1%3C1-m%20%5C%5C%20%5Ctext%7Bfor%20m%20equals%20negative%20integers%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
So, the statement "m-1 is always greater than 1-m" is false.
Because 1- m is greater than m-1 when m is a negative integer.
Therefore, I Disagree, because 1- m is greater than m-1 when m is a negative integer
Hello,
x²-5x-2=0
Δ=5²+4*2=33
==>x= (5-√33)/2 or x=(5+√33)/2
The answer to your question is <em>"A line with 4 tick marks labeled Cat, Dog, Rabbit, and Guinea Pig. Cat has 2 crosses, Dog has 3 crosses, Rabbit has 1 cross, and Guinea Pig has 3 crosses. The line is labeled Number of Pets, and title of graph is Pet Owners." </em>Because this is the only plot described that fits with the data from the table with the information on how many cats, dogs, rabbits, and guinea pigs there are.
I guess this will help you
Step-by-step explanation:
30 , 60 , 90 , 120, 150
,LCM of 12 and 30 is 60