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Zepler [3.9K]
3 years ago
8

Solve for b to the nearest hundredth:

Mathematics
1 answer:
lawyer [7]3 years ago
7 0
The right answer is B (b=-0.243)
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1. Name three examples of each of the types of properties of matter:
uysha [10]

Intensive properties and extensive properties are types of physical properties of matter. The terms intensive and extensive were first described by physical chemist and physicist Richard C. Tolman in 1917. Here's a look at what intensive and extensive properties are, examples of them, and how to tell them apart.


Intensive Properties

Intensive properties are bulk properties, which means they do not depend on the amount of matter that is present. Examples of intensive properties include:

Boiling point

Density

State of matter

Color

Melting point

Odor

Temperature

Refractive Index

Luster

Hardness

Ductility

Malleability

Intensive properties can be used to help identify a sample because these characteristics do not depend on the amount of sample, nor do they change according to conditions.


Extensive Properties

Extensive properties do depend on the amount of matter that is present. An extensive property is considered additive for subsystems. Examples of extensive properties include:

Volume

Mass

Size

Weight

Length

The ratio between two extensive properties is an intensive property. For example, mass and volume are extensive properties, but their ratio (density) is an intensive property of matter.

While extensive properties are great for describing a sample, they aren't very helpful identifying it because they can change according to sample size or conditions.


Way to Tell Intensive and Extensive Properties Apart

One easy way to tell whether a physical property is intensive or extensive is to take two identical samples of a substance and put them together. If this doubles the property (e.g., twice the mass, twice as long), it's an extensive property. If the property is unchanged by altering the sample size, it's an intensive property.

6 0
3 years ago
Here is a triangular pyramid and its net.
galben [10]

Answer:

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

Hence,

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

8 0
3 years ago
Oblicz.Pamiętaj o kolejności wykonywania działań
SashulF [63]

Answer:

33.275

Step-by-step explanation:

<u>1 step:</u> Difference in brackets

3.5-2\dfrac{1}{3}=3\dfrac{1}{2}-2\dfrac{1}{3}=(3-2)+\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=1+\dfrac{3-2}{3\cdot 2}=1+\dfrac{1}{6}=1\dfrac{1}{6}

<u>2 step:</u> 0.75\div\dfrac{1}{3}

0.75\div\dfrac{1}{3}=\dfrac{75}{100}\div \dfrac{1}{3}=\dfrac{3}{4}\times \dfrac{3}{1}=\dfrac{9}{4}

<u>3 step:</u> 1.28\div 0.04

1.28\div 0.04=128\div 4=32 \ \text{Move point two decimal places}

<u>4 step:</u>

2\dfrac{1}{4}\times 1\dfrac{1}{6}=\dfrac{2\cdot 4+1}{4}\times \dfrac{1\cdot 6+1}{6}=\dfrac{9}{4}\times \dfrac{7}{6}=\dfrac{63}{24}=\dfrac{21}{8}

<u>5 step:</u>

\dfrac{9}{4}+32-\dfrac{21}{8}+1.65=(32+1.65)+\left(\dfrac{9}{4}-\dfrac{21}{8}\right)=33.65+\dfrac{9\cdot 2-21}{8}=33.65-\dfrac{3}{8}=33.65-0.375=33.275

6 0
3 years ago
julio is payed 1.4 times his normal hourly rate for each hour he works over 30 hours in a week last week he worked 35 hours and
Morgarella [4.7K]
Divide 30/1.4 and 436.60 should give uu how much he makes in his normal hourly rate multiply that by 5 and subtract that number from 436.60
7 0
3 years ago
How old am i if 200 reduced by 2 times my age is 16
Rashid [163]
x-\ you're\ age\\\\&#10;200-2x=16\ \ \ | subtract\ 200\\\\&#10;-2x=-184\ \ \ | divide\ by\ -2\\\\&#10;x=92\\\\&#10;You\ are\ 92\ years\ old.
3 0
3 years ago
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