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3 years ago

Solve for b to the nearest hundredth:

Mathematics

1 answer:

lawyer [7]3 years ago

7 0

The right answer is B (b=-0.243)

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Luda [366]

He will have $840 in 24 months, which is two years.

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3 years ago

What is the missing statement in the proof?

Advocard [28]

A statement that defines who you are as a professional and what you hope to

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3 years ago

Text the answer 770-765-3026

Andre45 [30]

Answer:

A proportional relationship is there.

Step-by-step explanation:

Here in the table, the values of y are given corresponding to the values of x.

There are four sets of values of x and y.

We have to check whether the relationship is proportional or not.

Now, rate of change of y with respect to x will be from the first two pair of values is = $\frac{3.5 - (-1)}{-2 - (-8)} =0.75$

Again, rate of change of y with respect to x will be from the second two pair of values is = $\frac{12.5 - 3.5}{10 - (-2)} =0.75$

And, rate of change of y with respect to x will be from the third two pair of values is = $\frac{20-12.5}{20 - 10} =0.75$

So, the rate is always 0.75.

Therefore, a proportional relationship is there. (Answer)

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4 years ago

Read 2 more answers

Use the domain {-1, 0, 1, 2, 3} and plot the points on the graph that would best satisfy the equation. The bold grid marks repre

zubka84 [21]

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3 years ago

Bernie spends $6.50 on ingredients and cups for his lemonade stand. He charges $1.50 for each cup of lemonade. How many cups, x,

siniylev [52]

Answer:

18 cups.

Step-by-step explanation:

We are given that Bernie spends $6.50 on ingredients and cups for his lemonade stand. He charges $1.50 for each cup of lemonade. Inequality that represents this situation: $20\leq 1.50x-6.50$ .

To find number of cups x to make a profit of at least $20 we will use our given inequality.

$20\leq 1.50x-6.50$

$20+6.50\leq 1.50x$

$26.50\leq 1.50x$

$x\geq \frac{26.50}{1.50}$

$x\geq \frac{53}{3}$

$x\geq 17.6666666$

Therefore, in order to make a profit of at least $20 Bernie need to sell 18 cups of lemonade.

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3 years ago