what’s the answer and work for this? SOMEONE PLEASE TELL ME

#2 is the one I need help with

sleet_krkn [62]

Step-by-step explanation:

By arc sum Postulate of a circle:

2 x + 3x + 4x = 360°

9x = 360°

x = 360°/9

x = 40°

3x = 3* 40° = 120°

By inscribed angle theorem:

$m\angle 1= \frac {1}{2} \times 3x\\\\\therefore m\angle 1= \frac {1}{2} \times 120°\\\\\huge \red {\boxed {\therefore m\angle 1= 60°}}$

By tangent secant theorem:

$m\angle 2 = \frac {1}{2} \times 3x\\\\\therefore m\angle 2 = \frac {1}{2} \times 120°\\\\\huge \purple {\boxed {\therefore m\angle 2 = 60°}}$

Since, measure of central angle is equal to the measure of its corresponding minor arc.

$m\angle 3 = 3x\\\\\huge \pink {\boxed {\therefore m\angle 3 = 120°}}$

By angle sum Postulate of a triangle:

$m\angle 3 + 2 m\angle 4 = 180°\\\\120° + 2 m\angle 4 = 180° \\\\2 m\angle 4 = 180°- 120° \\\\2 m\angle 4 = 60° \\\\m\angle 4 = \frac {60°}{2} \\\\\huge \orange {\boxed {m\angle 4 =30°}}$

3 0

3 years ago

Which of the following is either a median or an altitude?

Blizzard [7]

Answer:

PR is an altitude

QT is a median.

Step-by-step explanation:

The altitude is the perpendicular height and the median is a line from 1 vertex to the middle of the opposite side.

5 0

3 years ago

andrea rents a bike for 8 hours and pays $42 for the rental tomorrow she wants the same bike but only needs it for 6 hours what

Annette [7]

Answer:

8x=42 where x is hourly cost

so x = 21/4

6*x = 63/2 $

Step-by-step explanation:

5 0

3 years ago

Consider <img src="https://tex.z-dn.net/?f=%24%5Ctriangle%20ABC%24%20such%20that%20%24BC%20%3D%203AC%24%20and%20%24%5Cangle%20A%

Gemiola [76]

The answer to the question is,

12 sin(∠B) = 2, 12 sin(∠C) = √3+√35

Sin rule is,

sin(A)/BC = sin(B)/AC = sin(C)/AB

sin(B) = (sin(A)×AC)/BC

sin(C) =(sin(B)×AB)/AC

To solve this question we apply sin rule,

Now we take

12 sin(∠B) =12 (sin(∠A)×AC)/BC

12 sin(∠B) =12 (sin(π/6)×(x/3x)) where ∠A =π/6 and AC=x, BC =3x

12 sin(∠B) =12 ((1/2)×(1/3))

12 sin(∠B) =12/6 = 2

12 sin(∠B) = 2

now we find the value of 12 sin(∠C)

12 sin(∠C) = 12(sin B)×(AB/BC)

now put the value of 12 sin(∠B) = 2

12 sin(∠C) = 2×(AB/BC)

12 sin(∠C) = (2/AC)×[AC×(cos(π/6))+BC×(cos B)]

12 sin(∠C) = 2×[cos(π/6)+(BC/AC)×(cos B)]

cos (π/6) = √3/2 and BC/AC =3

then

12 sin(∠C) = 2×[(√3/2)+3×(cos B)]

cos B= √1-sin²B

12 sin(∠C) = 2×[(√3/2)+3×√(1-sin²B)]

12 sin(∠B) = 2

sin B = 1/6

12 sin(∠C) = 2×[(√3/2)+3×√(1-(1/6)²]

12 sin(∠C) = 2×[(√3/2)+3×√1-(1/36)]

12 sin(∠C) = 2×[(√3/2)+3×√(36-1)/36]

12 sin(∠C) = 2×[(√3/2)+3×√(35/36)]

12 sin(∠C) = 2×[(√3/2)+(3/6)×√35]

12 sin(∠C) = 2×[(√3/2)+(1/2)×√35]

12 sin(∠C) = 2×[(1/2)(√3+√35)]

12 sin(∠C) = √3+√35

Hence the answer is,

12 sin(∠B) = 2, 12 sin(∠C) = √3+√35

Learn more about triangles rules from:

brainly.com/question/27998693

#SPJ10

6 0

2 years ago

Write a polynomial functionſ of least degree that has rational coefficients, a leading coefficient of 1, and the zeros 1,3, and

otez555 [7]

Answer:

f(x) = $x^{4} - 8x^{3} + 24x^{2} - 32x + 15$

Step-by-step explanation:

First of all, if 2 - i is a zero, then so is 2 + i

All you need to do now is multiply (x - 1)(x - 3)(x - 2 + i)(x - 2 - i)

I will do part of that multiplication

(x - 2 + i)(x - 2 - i) = $x^{2}$ - 2x - xi - 2x + 4 + 2i + xi - 2i - $i^{2}$

= $x^{2}$ - 4x + 5

So, now (x - 1)(x - 3)( $x^{2}$ - 4x + 5) = $x^{4} - 8x^{3} + 24x^{2} - 32x + 15$

I will let you finish that multiplication. I did some and you can do some. OK?

8 0

3 years ago

￼what’s the answer and work for this? SOMEONE PLEASE TELL ME

what’s the answer and work for this? SOMEONE PLEASE TELL ME