The result of the subtraction of 4365 and 3412 using octal numbers is of:
753.
<h3>What are octal numbers?</h3>
For octal numbers, each number is represented by three bits, as follows:
Then the binary representation of number 4365 is given as follows:
100011110101
The binary representation of number 3412 is given as follows:
011100001010
Then the following binary subtraction is made:
100011110101 - 011100001010
The result of this subtraction is of:
100011110101 - 011100001010 = 111101011
Then the octal result is given as follows:
111 101 011 = 753.
More can be learned about binary numbers at brainly.com/question/8649831
#SPJ1
Divide 1210 by 16 and write reminder divide until value zero
first step divide 1210 by 16 = 10
then 75 divide by 16 = 11
4
we can write 4 B A
in hexadecimal
Answer:
import java.util.*;
public class Main {
public static void main(String[] args)
{
Scanner scan = new Scanner();
double budget=0, num=0, total=0;
System.out.println("Your budget for the month? ");
budget=scan.nextDouble();
System.out.println("enter all expense, and after that type -9999 to quit: ");
while(num != -9999)
{
total+=num;
num=scan.nextDouble();
}
if(total<=budget)
{
System.out.println("under budget by ");
System.out.println(budget-total);
}
else
{
System.out.println("over budget by ");
System.out.println(total-budget);
}
}
}
Explanation:
- Take the budget as an input from user and store it to the budget variable.
- Loop until user has entered all his expenses and keep on adding them to the total variable.
- Check If the total is less than or equal to budget or otherwise, and then print the relevant message accordingly.
Answer:
to close an open application
