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Mrrafil [7]
2 years ago
6

Perimeter refers to the distance around 2-D figure and calculate perimeter, add the side lengths of the figure

Mathematics
1 answer:
viva [34]2 years ago
3 0

Answer:

True

Step-by-step explanation:

The perimeter is the combined length of all the side lengths of a figure.

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If you need an equation it is -3.4x=21.5

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Simplify using appropriate property: 5/7 X 1/5 + 5/7 X 3/5Simplify using appropriate property:
chubhunter [2.5K]

Answer:

4/7

Step-by-step explanation:

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8 0
3 years ago
Three houses are mapped on a coordinate grid.
Licemer1 [7]

Step-by-step explanation:

Let us consider the task to find the angle between vectors ES and EJ (the first letters are taken to name the vectors).

\overrightarrow{ES} = (4;4) - (4; -3) = \overrightarrow{(0; 7)}

ES

=(4;4)−(4;−3)=

(0;7)

​

\overrightarrow{EJ} = (-5; -4) - (4; -3) = \overrightarrow{(-9; -1)}

EJ

=(−5;−4)−(4;−3)=

(−9;−1)

​

cos \alpha=\frac{\overrightarrow{ES}*\overrightarrow{EJ}}{|\overrightarrow{EJ}|*|\overrightarrow{ES}|}cosα=

∣

EJ

∣∗∣

ES

∣

ES

∗

EJ

​

cos(a) = (0*(-9)+7*(-1)) / (7*9.055) = -0.11043;

a = 96,34°

Solution: 96 degrees.

6 0
3 years ago
Two runners one averaging 5 miles per hour and the other one averaging 4 miles per hour, start at the same place and run along t
Vikentia [17]

Answer:

The Distance cover by both the Runners is same = 10 miles  

Step-by-step explanation:

According to question ,

The Speed of first runners (S 1) = 5 miles per hour

The speed of second runners (S 2)  = 4 miles per hour

Let The Time taken by First runner (T 1 ) = T hour

But the second runner  arrives half hour after the first runner ,

I.e The Time taken by Second runner (T 2) = ( T + \frac{1}{2} )

Now from Distance = Speed × Time

Since both the runners start from same place and run along the same trail

SO ,Both the Distance cover by both are same , D 1 = D 2

i.e Speed 1 × Time 1 = Speed 2 × Time 2

    5 mph × T            =  4 mph   ×  ( T + \frac{1}{2} )

    5 T =  4 T + ( 4 × \frac{1}{2} )

Or,  5 T - 4 T = 2

∴       T    =  2 hour  ,

Time take by first = T1 = T = 2 hour

Time take by second = T2 = T + \frac{1}{2} = (2  +  \frac{1}{2} )hour = \frac{5}{2}

Now the Distance cover = Speed × Time

              Distance   (D1)          = 5 mph  × 2 hour = 10 mile

And        Distance    (D2)         =  4 mph  × \frac{5}{2} = 10 miles

Hence, As The Distance cover by both the Runners is same = 10 miles  Answer

5 0
3 years ago
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