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Sergio039 [100]
3 years ago
5

Plz help me my mom and dad don't know this

Mathematics
1 answer:
bezimeni [28]3 years ago
7 0
X/y
x=1 when y= 5
x=2 when y =10
the constant of proportionality = 1/5
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I need helpppppp asap
user100 [1]

Answer:

graph A

Step-by-step explanation:

When looking at a graph, there are two different axes. The vertical values--marked by the center up/down line--are "y-values"; and this is called the "y-axis"

The horizontal values--marked by the left/right line--are "x-values"; and this is called the "x-axis"

For the x-axis, values to the left side of the origin (the place where the y-axis and x-axis intercept) are smaller than 0--they are all negative values.

Values to the right side of the origin are positive--greater than 0.

For the y-axis, positive numbers are on the top half [once again, the midpoint / 0 is where the two lines are both = to 0; the origin] and negative numbers are on the bottom half.

Ordered pairs (points) are written as (x,y)

(x-value, y-value)

We are looking for a graph that decreases (along the y-axis), hits a point below the origin, and goes flat/stays constant.

When a graph is decreasing (note: we read graphs from left to right), the line of the graph is slanted downwards (it looks like a line going down).

So, if we look at the graphs, we can see Graph A descending, crossing the y-axis {crossing the middle line /vertical line / y-axis} at a value of -7, and then staying constant (it is no longer increasing or decreasing because the y-values stay the same)

hope this helps!!

4 0
1 year ago
The random variable X~(30,2^2) <br> Find p(X&lt;33) <br> Find p(X&gt;26)
Ostrovityanka [42]

Answer:

i) P(X<33)  = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

<u>Step(ii):-</u>

i)

Given that the random variable  X = 33

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-30}{2} = 1.5 >0

P(X<33) = P( Z<1.5)

              = 1- P(Z>1.5)

             = 1 - ( 0.5 - A(1.5))

             = 0.5 + 0.4232

  P(X<33)  = 0.9232

<u>Step(iii) :-</u>

Given that the random variable  X = 26

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-26}{2} = 3.5 >0

P(X>26)  = P( Z>3.5)

              = 0.5 - A(3.5)

              = 0.5 - 0.4990

             = 0.001

P(X>26) = 0.001

5 0
3 years ago
6x+9+2x<br> What is the answer
slavikrds [6]

Answer:

6x+9+2x

Step-by-step explanation:

8x+9

hope it helps uh

7 0
3 years ago
Read 2 more answers
Х<br> g(x)<br> -7<br> -4<br> -3<br> -4<br> *2<br> 1<br> 1<br> 2<br> -h statement in truon
s2008m [1.1K]

Answer:

and I have to be a good guy and a great guy and a good man to help him out and

Step-by-step explanation:

I think it's me and my name and it was the same thing you said before I am not a fan or something to lampguy55 8th grade but people are so much

8 0
3 years ago
If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No
Effectus [21]

If A and B are independent, then P(A\cap B)=P(A)P(B).

a.

P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)

P(A\cup B)=0.5+0.2-0.5\cdot0.2

\boxed{P(A\cup B)=0.6}

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)

P(A^c\cap B^c)=1-0.6

\boxed{P(A^c\cap B^c)=0.4}

c. DeMorgan's law can be used here too:

P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)

P(A^c\cup B^c)=1-0.5\cdot0.2

\boxed{P(A^c\cup B^c)=0.9}

4 0
3 years ago
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