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3 years ago

Students class Presidential Votes

Mathematics

1 answer:

nika2105 [10]3 years ago

5 0

I want to share my sunsets with you8182939282810iqlwkisjs

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The area of a rectangle is 64 square meters. If the length is 3 times the width, then find the dimensions of the rectangle. Roun

Anna71 [15]

Length:3x
width:x
3x•x=64
3x^2=64
x^2=21 1/3
x= about 4.6188
length:3(4.6188)=13.86 meters
width=4.62 meters

8 0

4 years ago

The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m

Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is $P(X=0) \approx 0.8659$

The probability of at least 1 failure in a 24-hour day is $P(X\geq 1 )\approx 0.3508$

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

$P(X)=\frac{e^{-\mu}\mu^x}{x!}$

Let X be the number of failures of a testing instrument.

We know that the mean $\mu = 0.018$ failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is $\mu=8\cdot 0.018=0.144$

$P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659$

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is $\mu=24\cdot 0.018=0.432$

$P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508$

3 0

4 years ago

Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers

Mars2501 [29]

Answer:

a) Let $\frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}$ .

Observe that

$\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.$

Observe that

$\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.$

Observe that

$\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}$

Let $\frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.$

Observe that

$\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}$

3 0

3 years ago

HELP ITS TIMED PLEASE IM BEGGING YOU

Blababa [14]

The answer is letter A and letter D

5 0

3 years ago

PLS HELP the FIRST PERSON TO ANSWER CORRECTLY I WILL MARK BRAINLIEST

Morgarella [4.7K]

Answer:

A. Zero

Step-by-step explanation:

12x+8=12x+8 - collecting like terms.

12x-12x=8-8

0=0

Hope it helps <3.

7 0

3 years ago