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2 years ago

WILL AMKR BRAINLIEST IF GOTTEN RIGHTTT!!!!

Mathematics

1 answer:

Juliette [100K]2 years ago

4 0

Answer:

1.06 sq inches

Step-by-step explanation:

its reasonable come on now

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Need help ASAP (Geometry) Fast!

suter [353]

6) arc length = 2*PI*R* degree/360
arc length = 2 * PI * 3 * 65/360
= 6*PI x 65/360
= 13/12*PI

Answer = C

7) drawing the lines as given would make a T shape with B being the mid point, so the answer would be C

3 0

3 years ago

Help me please 2(x-4) = 6x - 6

Dmitrij [34]

Answer:

-1/2

Step-by-step explanation:

2(x-4)=6x-6

2x-8=6x-6

2x-6x-8=-6

-4x-8=-6

-4x=-6+8

-4x=2

x=2/-4

simplify

x=-1/2

8 0

2 years ago

Read 2 more answers

Use the zero product property to find the solutions to the equation 6x^2 – 5x = 56.

frez [133]

Answer:

x = 7/2 or x = -8/3

Step-by-step explanation:

Solve for x over the real numbers:

6 x^2 - 5 x = 56

Divide both sides by 6:

x^2 - (5 x)/6 = 28/3

Add 25/144 to both sides:

x^2 - (5 x)/6 + 25/144 = 1369/144

Write the left hand side as a square:

(x - 5/12)^2 = 1369/144

Take the square root of both sides:

x - 5/12 = 37/12 or x - 5/12 = -37/12

Add 5/12 to both sides:

x = 7/2 or x - 5/12 = -37/12

Add 5/12 to both sides:

Answer: x = 7/2 or x = -8/3

8 0

3 years ago

Read 2 more answers

Tom is drawing a map of the block on which he lives, using a scale of 1 inch to 160 feet. The actual length of his block is 1,80

Basile [38]

The length of tom's block on his map is 11.25 inches

5 0

2 years ago

Read 2 more answers

In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day

nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

$P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33$

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

$P(A \cap B) = 0.42*0.25 = 0.105$

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

$P(B|A) = \frac{0.105}{0.33} = 0.3182$

31.82% probability that this day would be a winter day

6 0

2 years ago