You need to fill in the blank spaces in the chart.
For the first row, read the word form and try to put it into numbers. It would be 5,370.
Then, you need to put it into expanded form. This is a bit harder since you need to separate all of the numbers. It would be 5,000+300+70+2.
For the second row, you have to work backwards. This time it’s 50,370. Write it in standard form and word form as I taught you. Good luck!
Consider the equation 
.
First, you can use the substitution 
, then 
and equation becomes 
. This equation is quadratic, so
.
Then you can factor this equation:
.
Use the made substitution again:
.
You have in each brackets the expression like 
that is equal to 
. Thus,
![x^3+5=(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25}) ,\\x^3+1=(x+1)(x^2-x+1)](https://tex.z-dn.net/?f=%20x%5E3%2B5%3D%28x%2B%5Csqrt%5B3%5D%7B5%7D%29%28x%5E2-%5Csqrt%5B3%5D%7B5%7Dx%2B%5Csqrt%5B3%5D%7B25%7D%29%20%2C%5C%5Cx%5E3%2B1%3D%28x%2B1%29%28x%5E2-x%2B1%29%20%20%20)
and the equation is
![(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25})(x+1)(x^2-x+1)=0](https://tex.z-dn.net/?f=%20%28x%2B%5Csqrt%5B3%5D%7B5%7D%29%28x%5E2-%5Csqrt%5B3%5D%7B5%7Dx%2B%5Csqrt%5B3%5D%7B25%7D%29%28x%2B1%29%28x%5E2-x%2B1%29%3D0%20%20%20)
.
Here ![x_1=-\sqrt[3]{5} , x_2=-1](https://tex.z-dn.net/?f=%20x_1%3D-%5Csqrt%5B3%5D%7B5%7D%20%2C%20x_2%3D-1%20)
and you can sheck whether quadratic trinomials have real roots:
1. ![D_1=(-\sqrt[3]{5}) ^2-4\cdot \sqrt[3]{25}=\sqrt[3]{25} -4\sqrt[3]{25} =-3\sqrt[3]{25}](https://tex.z-dn.net/?f=%20D_1%3D%28-%5Csqrt%5B3%5D%7B5%7D%29%20%5E2-4%5Ccdot%20%5Csqrt%5B3%5D%7B25%7D%3D%5Csqrt%5B3%5D%7B25%7D%20-4%5Csqrt%5B3%5D%7B25%7D%20%3D-3%5Csqrt%5B3%5D%7B25%7D%20%20%3C0%20)
.
2. 
.
This means that quadratic trinomials don't have real roots.
Answer:
If you need complex roots, then
![x_{3,4}=\dfrac{\sqrt[3]{5}\pm i\sqrt{3\sqrt[3]{25}}}{2} ,\\ \\x_{5,6}=\dfrac{1\pm i\sqrt{3}}{2}](https://tex.z-dn.net/?f=%20x_%7B3%2C4%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B5%7D%5Cpm%20i%5Csqrt%7B3%5Csqrt%5B3%5D%7B25%7D%7D%7D%7B2%7D%20%20%20%2C%5C%5C%20%5C%5Cx_%7B5%2C6%7D%3D%5Cdfrac%7B1%5Cpm%20i%5Csqrt%7B3%7D%7D%7B2%7D%20%20%20%20)
.
The answer is 30 I believe
Answer:
2
Step-by-step explanation:
Area of a square = 
(<em>s is a side length)</em>
<em>24 = </em>
= 
= <em>s</em>
= <em>s</em>
<em>2</em> = <em>s</em>
