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Gennadij [26K]
3 years ago
7

ABC is isosceles AC=20 and BC= 3x-7

Mathematics
1 answer:
Brrunno [24]3 years ago
7 0

Answer:

x=9

Step-by-step explanation:

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Which expression is equivalent to - 14 -6?<br> A.-14 + (-6)<br> B.-14 -6 <br> C.14 +6<br> D.14 +(-6)
kykrilka [37]

Answer:

B

Step-by-step explanation:

4 0
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A bag is filled with 200 silver coins and 123 gold coins. What is the theoretical probability of not pulling out a silver coin
Simora [160]
62% because 200 silver coins out of 323 (total of all coins) is .619..., resulting in 62%
4 0
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You give the students information about taking liquids on a plane.
Lady bird [3.3K]
What is the maximum ml you can take with you on the plane??
5 0
3 years ago
1)Find the remainder when 4x2 + 2x + 1 is divided by (2x +3).
bagirrra123 [75]
<h2><em>Answers:</em></h2>
  1. <em> </em><em>7</em>
  2. <em>1</em><em>5</em><em>0</em>

<em>Please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em>

<em>hope</em><em> </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em> </em>

7 0
3 years ago
Which of the following is the complete list of roots for the polynomial function f (x) = (x squared 6 x 8) (x squared 6 x 13)? –
Sunny_sXe [5.5K]

The roots of the given polynomial function is {-4, -2, -3 + 2i, -3 - 2i}.

<h3>How to get the roots of the polynomial?</h3>

Here we have the polynomial function:

f(x) = (x^2 + 6x + 8)*(x^2 + 6x + 13)

So we just need to find the roots of the two quadratic functions, to do that, we use Bhaskara's formula.

For the first one, we have:

x = \frac{-6 \pm \sqrt{6^2 - 4*8} }{2} \\\\x = \frac{-6 \pm 2}{2}

So the two solutions are:

x = (-6 - 2)/2 = -4

x = (-6 + 2)/2 = -2

For the second quadratic we have:

x = \frac{-6 \pm \sqrt{6^2 - 4*13} }{2} \\\\x = \frac{-6 \pm 4i}{2}

So the two solutions are:

x = -3 + 2i

x = -3 - 2i

Finally, the list is:

{-4, -2, -3 + 2i, -3 - 2i}

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ4

8 0
2 years ago
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