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3 years ago

Calculate the acceleration of a moving object, given that the object is 500 g and has a a force of 6.5 n

Mathematics

2 answers:

ratelena [41]3 years ago

7 0

Hello!

$\large\boxed{a = 13m/s^{2}}$

Use the equation F = m · a to solve where:

F = total force (N)

m = mass (kg)

a = acceleration (m/s²)

We are given the force and mass, so we can plug these values into the equation to solve.

However, mass is used in kilograms, so we must convert from grams to kilograms:

1 kg = 1000 grams

Convert using dimensional analysis or proportions:

$500 g* \frac{1 kg}{1000g} = 0.5kg$

Plug in the force and mass to solve:

6.5 = 0.5(a)

Divide both sides by 0.5 (Multiply by 2)

a = 13 m/s²

mars1129 [50]3 years ago

3 0

Answer:

OKOKOKOKOKO

Step-by-step explanation:

OKOKOKOKOKOKOKOKOOKOOKO

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5^11 times 5^3 = 5^?

postnew [5]

Answer:

$5^{13}$

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2 years ago

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Light bulbs manufactured at a certain factory have a 3% probability of being defective. What is the probability that 5 out of a

Eddi Din [679]

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$3\%^5*97\%^{25}$

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3 years ago

2. Determine the sum of the first 400 ODD numbers.

il63 [147K]

Odd numbers take the form $2n-1$ , where $n\ge1$ is an integer. When $n=400$ , the last odd number would be 799. So we're adding

$S=1+3+5+\cdots+795+797+799$

By reversing the order of terms, we have

$S=799+797+795+\cdots+5+3+1$

and we can pair up terms in both sums at the same position to write

$2S=(1+799)+(3+797)+(5+795)+\cdots(795+5)+(797+3)+(799+1)$

so that we are basically adding 400 copies of 800, and from there we can find the value of the sum right away:

$2S=400\cdot800\implies S=160,000$

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We could also make use of the formulas,

$\displaystyle\sum_{i=1}^n1=n$

$\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2$

We have

$S=\displaystyle\sum_{i=1}^{400}(2i-1)=2\sum_{i=1}^{400}i-\sum_{i=1}^{400}1=400(400+1)-400=400^2=160,000$

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3 years ago