Solve for x. 2x-2=-12 please help

Mathematics

2 answers:

lukranit [14]2 years ago

4 0

Answer:

-5

Step-by-step explanation:

2x=-10

x=-5

Finger [1]2 years ago

3 0

Answer:

x = -5

Step-by-step explanation:

2x - 2 = -12

(Add 2 on both sides)

2x - 2 (+2) = -12 (+2)

(simplify)

2x=-10

(Divide by 2 on both sides)

2x/2 = -10/2

(Simplify)

x = -5

Hope this helps :)

You might be interested in

Which number below best represents a credit of $17.16?

PIT_PIT [208]

B. 17.16 represents a credit of $17.16; "credits" mean that you're receiving something, so it's added. A is incorrect because it shows the money being taken away and that isn't what a credit does. C and D aren't even the same amount of money in the question, so they aren't your answer either.

3 0

2 years ago

Read 2 more answers

How do I do this? please detail steps.

vladimir2022 [97]

Define
${x} = \left[\begin{array}{ccc}x_{1}\\x_{2}\end{array}\right]$

Then
x₁ = cos(t) x₁(0) + sin(t) x₂(0)
x₂ = -sin(t) x₁(0) + cos(t) x₂(0)

Differentiate to obtain
x₁' = -sin(t) x₁(0) + cos(t) x₂(0)
x₂' = -cos(t) x₁(0) - sin(t) x₂(0)

That is,
$\dot{x} = \left[\begin{array}{ccc}-sin(t)&cos(t)\\-cos(t)&-sin(t)\end{array}\right] x(0)$

Note that
$\left[\begin{array}{ccc}0&1\\-1&09\end{array}\right] \left[\begin{array}{ccc}cos(t)&sin(t)\\-sin(t)&cos(t)\end{array}\right] = \left[\begin{array}{ccc}-sin(t)&cos(t)\\-cos(t)&-sin(t)\end{array}\right]$

Therefore
$x(t) = \left[\begin{array}{ccc}0&1\\-1&0\end{array}\right] x(t)$

7 0

2 years ago

ΔABC has vertices A(0,10), B(4,10), and C(-2,4).

laiz [17]

A simple diagram will show you the intersection of altitudes is in the 2nd quadrant. It must have x-coordinate -2, as the altitude to the "base" y=10 must be the vertical line through (-2, 4).

The appropriate choice is ...

... C: (-2, 12)