Answer: idk
Step-by-step explanation:
Answer:
Could you please add a photo or the quadratic function?
Answer:
The 32nd term of the arithmetic sequence is -386.
Step-by-step explanation:
Given: The arithmetic sequence where and
We have to find the 32nd term of the arithmetic sequence.
Consider the given sequence with and
We know , For a given sequence in an Arithmetic sequence with first term and common difference d , we have,
We first find the common difference "d".
, we have,
Solve for d , we have,
-88= 8d
d = - 11
Thus, 32nd term is
Thus, The 32nd term of the arithmetic sequence is -386.
Hello!
The mean is 12
The data has a standard deviation of 4
Look and see how far away 18 is from 12 using 4
12 + 4 = 16
16 is one deviation
16 + 4 = 20
20 is two deviation
18 is right in the middle
The answer is C. 1.5 deviations
Hope this helps!
Answer:
Hello There!!
Step-by-step explanation:
Firstly,select three ordered pairs from the table. Secondly,substitute the first pair of values in to the form of the quadratic equation: f(x) = ax^2 + bx + c and then solve for a.
hope this helps,have a great day!!
~Pinky~