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Liula [17]
2 years ago
10

Plz Find the volume of the triangular prism shown below.

Mathematics
1 answer:
jonny [76]2 years ago
4 0

Answer:

this is required answer.

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Find an ordered pair , x y that is a solution to the equation. 3x-y=1
NemiM [27]

Answer:

2,5

Step-by-step explanation:

2,5 is just one of the many solutions to this problem. you can just take a random number for x, for example 2. your equation will look like this 3(2)-y=1. now you just solve for y. 3x2=6. 6-1=5. so y=5.

3 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
vfiekz [6]

Answer:

The slope is 3/2 and the y intercept is 4

Step-by-step explanation:

We want to write in the form

y = mx+b where m is the slope and b is the y intercept

-3x+2y = 8

Add 3x to each side

-3x+3x+2y = 3x+8

2y = 3x+8

Divide each side by 2

2y/2 = 3x/2 + 8/2

y = 3/2x +4

The slope is 3/2 and the y intercept is 4

7 0
3 years ago
Write the number in standard form.
WINSTONCH [101]

Answer:

The number in standard form is 233.64

8 0
2 years ago
A spinner is spun 22 times. What is the experimental probability of spinning either a 5 or 6?
Nesterboy [21]

Answer:

quedarse corona abuelos pelear

6 0
3 years ago
I don't get it and I have tried it multiple ways
jasenka [17]

9514 1404 393

Answer:

  9350 m²

Step-by-step explanation:

There are several ways you can go at this. Here are 3 of them:

  1. along an extension of the lower right vertical edge, divide the figure into a rectangle and a right triangle.
  2. between the upper left corner and the inside corner at lower right draw a diagonal line to divide the figure into a trapezoid and a triangle.
  3. subtract the area of the trapezoid at the right from the area of the bounding rectangle

__

The relevant formulas for area are ...

  rectangle: A = LW . . . . . . . . . . . length times width

  trapezoid: A = (1/2)(b1 +b2)h . . . b1, b2 are the bases, h is the height

  triangle: A = (1/2)bh . . . . . . . . . . . b is the base, h is the height

__

Here's what those computations look like:

1. rectangle: 60m wide by 80 m high = 4800 m².

  right triangle: base 190-60 = 130 m; height = 80-10 = 70 m.

     area = (1/2)(130 m)(70 m) = 4550 m²

  figure area = 4800 m² +4550 m² = 9350 m² . . . . area of figure

__

2. The trapezoid has bases of 80 m and 10 m, and a height of 60 m. Its area is ...

  A = (1/2)(80 m +10 m)(60 m) = 2700 m²

The triangle has a base of 190 m and a height of 80-10 = 70 m. Its area is ...

  A = (1/2)(190 m)(70 m) = 6650 m²

Then the total area is 2700 m² +6650 m² = 9350 m² . . . total area

__

3. The bounding rectangle is 190 m by 80 m, so its area is ...

  A = LW = (190 m)(80 m) = 15200 m²

The (negative) trapezoid at right has bases of 10 m and 80 m, and a width of 190-60 = 130 m. Its area is ...

  A = (1/2)(10 m +80 m)(130 m) = 5850 m²

The area of the figure is the difference between these:

  figure area = 15200 m² -5850 m² = 9350 m² . . . figure area

7 0
3 years ago
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