Having a Hitchhiker’s Thumb (T) is dominant over not having Hitchhiker’s Thumb (t). If a person that is Tt has children with a p

Question

2 years ago

11

Having a Hitchhiker’s Thumb (T) is dominant over not having Hitchhiker’s Thumb (t). If a person that is Tt has children with a p

erson that is Tt, what is the probability of their children that will not have a Hitchhiker’s Thumb?
a
0%
b
25%
c
50%
d
75%

Biology

2 answers:

Eduardwww [97] · Answer 1 · 2022-10-23T23:19:25+03:00

Answer:

B. 25%

Explanation: If you draw a Punnett square you see that you get TT, Tt, Tt, and tt. Now if T (Hitchhikers thumb) is dominant over t (non hitchhikers thumb) TT, Tt, and Tt are all going to have hitchhikers thumb and only tt won't have hitchhikers thumb. 1 out of 4 is equal to 25%.

Len [333] · Answer 2 · 2022-10-24T00:21:03+03:00

Len [333]2 years ago

3 0

The answer is B. 25%