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Elan Coil [88]
3 years ago
12

If a⋅b+c⋅d=12, and a,b,c and d are all integers greater than 1, how many values are possible for a, if a, b, c, and d are not ne

cessarily distinct?
Mathematics
1 answer:
Dmitriy789 [7]3 years ago
8 0

Answer:

hajajhagshausuwuw8h1v2os q

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Which number has a 3 that is 10 times as much as the 3 in 24,345 A) 44,578 B) 89,236 C) 13,847 D) 56,243
inn [45]

The 3 in 24,345 has a value of 300. A number 10 times that would have a value of 300*10 or 3,000. The 3 in choice C has a value of 3,000 so C is the right answer.

4 0
3 years ago
The sum of two consecutive odd integers is 316. Find the two odd integers.
Tcecarenko [31]
1, 3, 5, 7, 9 ......
notice, there are consecutive odd integers, every other number
skip one, another, skip one, another and so on

so, from 1 to 3, is 1 + 2 =3
5 is 3 +2
7 is 5+2
and so on

let us pick an odd integer, hmmm say "a"
to find the next odd one, it'd be "a + 2" of course :)

we know their sum is 316
so \bf a+(a+2)=316\impliedby \textit{solve for "a"}

once you found "a", the next one is, well, "a + 2" :)
5 0
3 years ago
2thousands pluse 14hundreds
snow_tiger [21]
2.000 pluse 4.00=600.000
4 pluse 2=6
thousand pluse hundreds=hundre thousandths


3 0
3 years ago
Read 2 more answers
A car is moving with a velocity (3.0 m/s) x̂ + (1.0 m/s) ŷ and 3.0 seconds later its velocity is (6.0 m/s) x̂ - (3.0 m/s) ŷ. Wha
Mars2501 [29]

Here we know that the initial velocity of the car is given by:

V_i=(3.0\hat x+1.0\hat y)m/s

And the final velocity of the car is given by:

V_f=(6.0\hat x-3.0\hat y)m/s

It took 3 seconds to attain the final velocity, so we have t=3 s

Therefore, the acceleration can be obtained by:

V_f-V_i=a\times t

a=\frac{V_f-V_i}{t}

Plugging the values of the initial, final velocity and the time, we get:

a= \frac{(6\hat x-3\hat y)-(3 \hat x+1 \hat y)}{3} =\frac{6\hat x-3 \hat y -3 \hat x-1 \hat y}{3} =\frac{3 \hat x-4 \hat y}{3}

So the acceleration of the car is given by:

a=\frac{3 \hat x}{3} -\frac{4 \hat y}{3} =1 \hat x- \frac{4}{3} \hat y

Now we need to find the direction of the average acceleration of the car:

\theta=tan^{-1} \frac{y}{x}

Here, x and y are the coefficients of the 'x' and 'y' components of the vector:

\theta=tan^{-1}(\frac{-\frac{4}{3} }{1} )=tan^{-1}(\frac{-4}{3}) =-53.13^\circ

Therefore, the direction of the average acceleration of the car is -53.13^\circ.

8 0
3 years ago
I need help, my teacher didnt teach up this​
nlexa [21]

Answer:

The volume is <u>1539.38</u>

Step-by-step explanation:

7 0
3 years ago
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