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3 years ago

8

A salesperson at a jewelry store earns 3% commission each week. Last week, heidi sold $530 worth of jewelry. How much did make

in commission? How much did the jewelry store make from sales?

1 answer:

Ivenika [448]3 years ago

7 0

Answer:

Heidi made $15.90 total

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Solve for p. −4.5 + p6= −18.9

Vesna [10]

Answer:

-2.4

Step-by-step explanation:

Given data

We have the expression before us as

−4.5 + p6= −18.9

Collect like terms

p6= −18.9+4.5

p6= -14.4

Divide both sides by 6

p= -14.4/6

p=-2.4

Hence the value of p= -2.4

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3 years ago

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F(x) = 2x2 – x + 9<br> Find f (4)

Alex

Answer:

45

Step-by-step explanation:

F(-4). F(x) = 2x^2 - x + 9

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3 years ago

What is the value of 5,sixths divided by 3,sevenths?

Alexus [3.1K]

5/6 divided by 3/7?

simple mi amigo!~

7* 5= 35

3*6= 18

= 35/18

= 1 17/18

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2 years ago

What do u think the answer is !!

AveGali [126]

Is that the full question, because it doesn't make sense to me :/

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2 years ago

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What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

<u>Step 2: Find Arc Length</u>

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

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2 years ago