Find the value of x. Then find the measure of each labeled angle

Mathematics

1 answer:

Artyom0805 [142]2 years ago

7 0

Step-by-step explanation:

Question 10 :

3x + 6 = 4x – 12 ( reason: corresponding angles due to parallel lines)

simplify and get x, thus x = 18

to find 3x + 6 or 4x - 12(which is both the same),

3(18) + 6 = 60° , 4(18) - 12 = 60°

Question 11:

2x + 24 + x = 180 ( reason: interior angles due to parallel lines)

simplify again to get x, you will get x = 52

then find the individual by subbing in the value of x into the equation.

so 2x + 24 = 2(52)+24 = 128° and x = 52°

You might be interested in

find the point on the terminal side of θ = negative three pi divided by four that has an x coordinate of negative 1

Mila [183]

Check the picture below, is a negative angle, thus, is going "clockwise"

$\bf tan(\theta)=\cfrac{opposite}{adjacent}\qquad tan\left( -\frac{3\pi }{4} \right)=\cfrac{y}{x}\implies tan\left( -\frac{3\pi }{4} \right)=\cfrac{y}{-1}
\\\\\\
-1\cdot tan\left( -\frac{3\pi }{4} \right)=y\implies -1\cdot \cfrac{sin\left( -\frac{3\pi }{4} \right)}{cos\left( -\frac{3\pi }{4} \right)}=y
\\\\\\
-1\cdot \cfrac{-1}{-1}=y\implies -1$

4 0

3 years ago

Hello help if u dont know dont even try to comment.

aniked [119]

Answer:

distance = 8.35 inch

Step-by-step explanation:

here's your solution

=> scale is , 1 inch = 20 feet

=> distance between room in feet = 167 feet

=> so, distance in inch = 167/20

=> distance = 8.35 inch

hope it helps

6 0

3 years ago

When given a quadratic equation, how do I graph it, and find the vertex?

NemiM [27]

So let’s say the equation is x^2 (x squared) -4x + 8 = 0. So you have to eventually graph a palabara. So to get the vertex, you have to find the line of symmetry (this plays a big part). So the formula for the line of symmetry is x= -b/2a. So A is this equation is 1. B is -4. C is 8. So you would plug these numbers in and you get 2. So (2,0) is your like of symmetry. Now you have to plug 2 back in for x. So when you do that you get 4 so the vertex is (2,4). So the vertex is (2, 4) and basically what the vertex is is it is the highest or lowest point of a palabara. So you can tel if it opens up or down by looking is A is negative or positive. If A is negative the it opens down. If it is positive then it opens up. So now you just put points in. Create a t chart. Like x/y. So when X is 1 for example, y is 5. So you graph (1, 5) and you graph the point that is the same distance from the line of symmetry. You do this until you have 5 points. I hope this helps. It’s hard to teach this over text.

4 0

3 years ago

prove that the quadrilateral whose vertices are the points A(-1,1), B(-3,4), C(1,5) and D(3,2) is a parallelogram.

Vsevolod [243]

Answer:

Since $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ , then the quadrilateral ABCD is a parallelogram.

Step-by-step explanation:

First, we label each point of the quadrilateral with the help of a graphing tool. If the quadrilateral ABCD is a parallelogram, then $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ . If we know that $A(x,y) =(-1, 1)$ , $B(x,y) =(-3,4)$ , $C(x,y) = (1,5)$ and $D(x,y) = (3,2)$ , then the measure of each vector is, respectively: