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Nataly [62]
3 years ago
14

What is the LCM of 20 and 40? 5 10 20 40

Mathematics
1 answer:
zepelin [54]3 years ago
4 0

Answer:

i think this is the answer

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Aleks04 [339]
Divide -11 \frac{1}{5} by 5. Or multiply it by 1/5.

You get - 56/25 or -2 \frac{6}{25} pounds per month. 
5 0
4 years ago
Who invited math?? Please answer!!!!!
maksim [4K]

Answer:

Ancient Greeks

Beginning in the 6th century BC with the Pythagoreans, with Greek mathematics the Ancient Greeks began a systematic study of mathematics as a subject in its own right. Around 300 BC, Euclid introduced the axiomatic method still used in mathematics today, consisting of definition, axiom, theorem, and proof.

Step-by-step explanation:

6 0
3 years ago
What is the simplified expression for 6(2(y+x))?
koban [17]
It should be B I know how to do it
5 0
3 years ago
Read 2 more answers
Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
Set up and solve an equation for the value of x. Use the value of x and a relevant angle relationship in the diagram
Fudgin [204]

Answer:

x and EAF are 27 degrees

Step-by-step explanation:

Since GAF is a right angle as indicated by the little square, GAC and CAF must add up to 90 degrees. Therefore, x is 90-63=27 degrees. The situation is the same for angle EAF. Hope this helps!

7 0
3 years ago
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