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Studentka2010 [4]
3 years ago
11

Find the value of given expression

04%7D%20" id="TexFormula1" title=" \sqrt{5688 \times 5688 \times 4} " alt=" \sqrt{5688 \times 5688 \times 4} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Black_prince [1.1K]3 years ago
7 0

Answer:

√{5688×5688×4}=√{5688²×2²)==±11376

vazorg [7]3 years ago
7 0

Step-by-step explanation:

The answer will be-+ 11376

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Which of the following is equivalent to the complex number i^6?
Reptile [31]

Answer:

-1

Step-by-step explanation:

i is √-1

i^2 is -1

i^3 is -i

i^4 is 1

This cycle repeats itself every 4 powers

so i^6 is -1

3 0
3 years ago
Y=1/3x-4 plz answer now
MA_775_DIABLO [31]

Answer: -4

Step-by-step explanation:

5 0
3 years ago
Find the equation of the linear function represented by the table below
Mariana [72]

Answer:

X-3=Y

Step-by-step explanation:

-3-3=-6

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4 0
3 years ago
Find the 75th term of the arithmetic sequence -17, -13, -9....
Sphinxa [80]

Answer:

The 75th term of the arithmetic sequence -17, -13, -9.... is:

a_{75}=279

Step-by-step explanation:

Given the sequence

-17, -13, -9....

An arithmetic sequence has a constant difference 'd' and is defined by  

a_n=a_1+\left(n-1\right)d

computing the differences of all the adjacent terms

-13-\left(-17\right)=4,\:\quad \:-9-\left(-13\right)=4

The difference between all the adjacent terms is the same and equal to

d=4

The first element of the sequence is:

a_1=-17

now substitute d=4 and a_1=-17 in the nth term of the sequence

a_n=a_1+\left(n-1\right)d

a_n=4\left(n-1\right)-17

a_n=4n-21

Now, substitute n = 75 in the a_n=4n-21 sequence to determine the 75th sequence

a_n=4n-21

a_{75}=4\left(75\right)-21

a_{75}=300-21

a_{75}=279

Therefore,  the 75th term of the arithmetic sequence -17, -13, -9.... is:

a_{75}=279

3 0
3 years ago
What is the value of the expression 6<br> ( -11.5)?
telo118 [61]

Answer:

-69

Step-by-step explanation:

6(-11.5) looks like 6*-11.5 to me which is -69.

4 0
3 years ago
Read 2 more answers
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