Answer:
see explanation
Step-by-step explanation:
Using the Addition formula for sine
sin(x ± y) = sinxcosy ± cosxsiny
Consider the left side
sin(360 - Θ ), then
= sin360°cosΘ - cos360°sinΘ
= 0 × cosΘ - 1 × sinΘ
= 0 - sinΘ = - sinΘ → verified
Answer:
t distribution behaves like standard normal distribution as the number of freedom increases.
Step-by-step explanation:
The question is missing. I will give a general information on t distribution.
t-distribution is used instead of normal distribution when the <em>sample size is small (usually smaller than 30) </em>or <em>population standard deviation is unknown</em>.
Degrees of freedom is the number of values in a sample that are free to vary. As the number of degrees of freedom for a t-distribution increases, the distribution looks more like normal distribution and follows the same characteristics.
Answer:
3.5/1 (or just 3.5)
Step-by-step explanation:
If y = a/n, then the constant proportionality is 3.5/1 or 7/2
Think of this as "rise over run" (we are basically finding the slope)
You're assuming that this data set represents all of Mrs. Hassaan's pupils. Certain students could be missing from the histogram - for instance, there could be one or two students who missed the test, but for certain reasons will be taking a make-up exam. Their grade would not be recording in this data set, but they still contribute to the class size, and so would be unaccounted for here.
(12x^4 + 17x^3 + 8x - 40) ÷ (x + 2)
<span> =<span><span><span><span><span><span><span>12<span>x^4</span></span>+<span>17<span>x^3</span></span></span>+<span>8x</span></span>−40 / </span><span>x+2</span></span></span></span></span><span> =<span><span><span><span><span>(<span>x+2</span>)</span><span>(<span><span><span><span>12<span>x^3</span></span>−<span>7<span>x^2</span></span></span>+<span>14x</span></span>−20</span>) / </span></span><span>x+2</span></span></span></span></span><span> =<span><span><span><span>12<span>x^3</span></span>−<span>7<span>x^2</span></span></span>+<span>14x</span></span>−<span>20</span></span></span>