To get from 8.4 to 10 in multiplication, we need to multiply 8.4 by 10/8.4
That means that if we multiply 30 by 10/8.4 we get the answer
which is 35,714
The same with the other
8.4 times 100/30 = 28
The correct choice of this question with the given polynomial is <em>"The zeros are </em>-2<em> and </em>8<em>, because the factors of g are (x + </em>2<em>) and (x - </em>8<em>)"</em>. (Correct choice: H)
<h3>How to analyze a second orden polynomial with constant coefficients</h3>
In this case we have a second order polynomial of the form <em>x² - (r₁ + r₂) · x + r₁ · r₂</em>, whose solution is <em>(x - r₁) · (x - r₂)</em> and where <em>r₁</em> and <em>r₂</em> are the roots of the polynomial, which can be real or complex numbers but never both according the fundamental theorem of algebra.
If we know that <em>g(x) =</em> <em>x² -</em> 6 <em>· x -</em> 16, then the <em>factored</em> form of the expression is <em>g(x) = (x - </em>8<em>) · (x + </em>2<em>)</em>. Hence, the correct choice of this question with the given polynomial is <em>"The zeros are </em>-2<em> and </em>8<em>, because the factors of g are (x + </em>2<em>) and (x - </em>8<em>)"</em>. 
To learn more on polynomials, we kindly invite to check this verified question: brainly.com/question/11536910
Not to seem rude, but you might have better luck in Business. Unless someone here know accounting lol
You don't have a question in there but I can tell you that the quadratic formula that is shown is not quite correct.
<span>x = -b ± √b2 - 4ac 2a
For one thing, the first 3 terms should ALL be divided by 2a
The square root symbol should be extended from b^2 through 4ac
The division symbol is missing.
So the quadratic formula SHOULD read:
x = [-b +- sq root (b^2 - 4ac) ] / 2a
Also I have attached a graphic of the quadratic formula.
</span>
Answer: There is one solution to the given equation.
Step-by-step explanation: We are given to find the number of solutions to the following equation :

Since the given equation is linear in one variable x, so it will have only one solution.
The solution of equation (i) is given by

Thus, there is one solution to the given equation.