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kari74 [83]
3 years ago
11

The quadratic formula allows us to find ___

Mathematics
1 answer:
loris [4]3 years ago
3 0

Answer:

Factor.

Step-by-step explanation:

In Mathematics, the quadratic formula is used for determining the two factors (roots) of any quadratic equation.

The standard form of a quadratic equation is ax² + bx + c = 0

Mathematically, the quadratic equation is given by the formula;

x = \frac {-b \; \pm \sqrt {b^{2} - 4ac}}{2a}

Hence, the quadratic formula allows us to find factor solutions to any quadratic equation.

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Which set of measurements could be the side lengths of a triangle? please help!
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3 years ago
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4.58 x 10^-5



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3 years ago
Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
3 years ago
I need help really quick
JulsSmile [24]

Answer:

15

Step-by-step explanation:

6 0
3 years ago
A parking garage has 6 levels . Each level has 15 rows. Each row has the same number of parking spaces . There are 2,250 parking
Vika [28.1K]
6*15=90 rows in total.
2250/90=25 spaces in a row
6 0
3 years ago
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