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geniusboy [140]
4 years ago
7

Two standard number cubes are thrown. Find the probability that the sum of the numbers showing is ten given that the first numbe

r cube shows a four.
Mathematics
1 answer:
Sergio [31]4 years ago
3 0

Given that the first number shows up as four. The second number should be six so that the sum would be ten. Therefore, its probability should be 1/6.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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6х + 4y + 2z = 32<br>3х - 3y - z = 19<br>3х + 2y + z = 32<br>x = ?<br>y = ?<br>z = ?​
blsea [12.9K]

×=12

y=9

z=2 not sure I'm right

3 0
3 years ago
The Sum Of Two Numbers Is 18 And Their Difference Is 4
Murljashka [212]

Answer:

The two numbers are 7 and 11.

Step-by-step explanation:

x represent the first number.

y represent the second number.

x + y = 18

x - y =  4

2x = 22

x = 11

x - y = 4

(11) - y = 4

y = 7

3 0
4 years ago
Solve for h <br> h/6 - 1 = -3
AURORKA [14]
H = -12

If you add 1 on both sides you get
h/6 = -2
Then Multiply 6 on both sides and you get h = -12
Thats your answer.
6 0
3 years ago
What is the factored form of the function f(x)=x^3+8x^2+5x−50?
Inga [223]

Answer:

the factors of  f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

Step-by-step explanation:

We need to factorise the function f(x)=x^3+8x^2+5x-50

If a number is a factor of this function than it must be completely divisible by last co-efficient. Our last co-efficient is -50

Checking few numbers:

f(1)=(1)^{3}+8(1)^2+5(1)-50\\f(1)=1+8+5-50\\f(1)=-32\\Now \ putting \ x= 2 \\f(2)=(2)^{3}+8(2)^2+5(2)-50\\f(2)=8+8(4)+10-50\\f(2)=8+32+10-50\\f(2)=0

So, f(2)=0 which means x-2 is a factor of the given function. Now we will perform long division of x^3+8x^2+5x-50 by (x-2) to find other factors

The long division is shown in figure attached.

After long division we get: x^2+10x+25

The equation x^2+10x+25 can be further simplified as: (x+5)(x+5) or (x+5)^2

So, the factors of  f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)

3 0
4 years ago
Which of the following vectors are orthogonal to (1,5)? Check all that apply
Andre45 [30]
We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal

</span><span>A. (-2,5)
</span>(-2,5)*(1,5)-------> -2*1+5*5=23-----------> <span>are not orthogonal 

</span><span>B. (10,-2)
</span>(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are  orthogonal 

<span>C. (-1,-5)
</span>(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal 

<span>D. (-5,1)
</span>(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are  orthogonal 

the answer is 
B. (10,-2) and D. (-5,1)  are  orthogonal  to  (1,5)
7 0
3 years ago
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