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Furkat [3]
2 years ago
13

Which is greater: -3 or 1/6 * They are equal 3 1/6 It depends

Mathematics
1 answer:
nasty-shy [4]2 years ago
6 0
The answer is 1/6 because it is not negative
You might be interested in
What is a possible solution to -7x+4>-3x-6
arsen [322]

-7x + 4 > -3x - 6

+7x           +7x

4 > 4x - 6

+6            +6

10 > 4x

---    ---

4        4 =   2.5 > x

So anything under 2.5

4 0
2 years ago
62. Which of the following equations is equivalent
Arte-miy333 [17]

Answer:

B.-2x = 6

Step-by-step explanation:

3x - 4 = 5x + 2

3x-5x = 2+4

-2x=6

6 0
3 years ago
On a coordinate plane, a shape is plotted with vertices of (3, 1), (0, 4), (3, 7), and (6, 4). what is the area of the shape if
QveST [7]
Let
<span>A (3, 1)
B (0, 4)
C(3, 7)
D (6, 4)

step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> dAB=√[(4-1)²+(0-3)²]-----> dAB=√18 cm

step 2
find the distance CD
d=√[(y2-y1)²+(x2-x1)²]------> dCD=√[(4-7)²+(6-3)²]-----> dCD=√18 cm

step 3
find the distance AD
d=√[(y2-y1)²+(x2-x1)²]------> dAD=√[(4-1)²+(6-3)²]-----> dAD=√18 cm

step 4
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> dBC=√[(7-4)²+(3-0)²]-----> dBC=√18 cm

step 5
find slope AB and CD
m=(y2-y1)/(x2-x1)
mAB=-1
mCD=-1
AB and CD are parallel and AB=CD

step 6
find slope AD and BC
m=(y2-y1)/(x2-x1)
mAD=1
mBC=1
AD and BC are parallel and AD=BC
and 
AB and AD are perpendicular 
BC and CD are perpendicular

therefore
the shape is a square wit length side √18 cm

area of a square=b²
b is the length side of a square
area of a square=(√18)²------> 18 cm²

the answer is
18 cm²

see the attached figure


6 0
3 years ago
A study was recently conducted to estimate the mean cholesterol for adult males over the age of 55 years. From a random sample o
Komok [63]

Answer:  Correct critical value = 2.2622

Step-by-step explanation:

Confidence interval for population mean when population standard deviation is unknown:

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}} , where \overline{x} = sample mean, n= sample size, s= sample standard deviation, t_{\alpha/2} = two-tailed t value.

As per given: n= 10

degree of freedom : df = n-1=9

\overline{x}=242.6\\\\s=73.33\\\\\alpha=5\%=0.05

Critical t-value : t_{\alpha/2,df}=t_{0.05/2,9}=t_{0.025,9}=2.2622

So, the 95 percent confidence interval estimate for the​ mean :

242.6\pm (2.2622)\dfrac{73.33}{\sqrt{10}}\\\\=242.6\pm (2.2622)(23.19)\\\\\approx242.6\pm52.46\\\\=(242.6-52.46,\ 242.6+52.46)\\\\=(190.14,\ 295.06)

The 95 percent confidence interval estimate for the​ mean:(190.14, 295.06)

8 0
2 years ago
-11× (-4) =___<br><br> 44 2/15<br><br> - 44 2/15<br><br> - 49<br><br> 49
pantera1 [17]

Answer:

44

Step-by-step explanation:

-×-=+

11×4=44

so it's equal to =+44

3 0
2 years ago
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