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Ksenya-84 [330]
3 years ago
12

X2 + 24x + 141.5 = 0

Mathematics
1 answer:
Tasya [4]3 years ago
4 0

Answer

x =(24-√816)/2=12-2√ 51 = -2.283

x =(24+√816)/2=12+2√ 51 = 26.283

Step-by-step explanation:

(Same thing)

x =(24-√816)/2=12-2√ 51 = -2.283

x =(24+√816)/2=12+2√ 51 = 26.283

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Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, n(S)=6

Now, probability of rolling a 3 is given as:

P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

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Not to seem rude, but you might have better luck in Business. Unless someone here know accounting lol

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Step-by-step explanation:

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Step-by-step explanation:

Hope this helps! ^^

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