In the figure, m<2 = 83, and m<21 = 68. Find the measure of each angle
1 answer:
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<u>Answer:</u>
C. Left-handed: 48, Right-handed: 504
D. Left-handed: 30, Right-handed: 315
<u>Step-by-step explanation:</u>
We are given that there are 58 left-handed students and 609 right-handed students at East Middle School and these numbers of students are proportional to the number of left and right handed students at East Middle School.
Given the above information, we are are to determine which two options could be the the numbers of left-handed and right-handed students at West Junior High.
Ratio of right handed to left handed students at East Middle School =
Checking for ratios of the given options:
A.
B.
C.
D.
E.
Therefore, the possible numbers of left-handed and right-handed students at West Junior High could be C. Left-handed: 48, Right-handed: 504 and D. Left-handed: 30, Right-handed: 315.
Answer: 7 Switches will be made.
Step-by-step explanation:
number of switches
number of switches
- however you cannot have a fraction of a switch so you must round it to a whole number, which in this case is 7.
Answer:
1/1000
Step-by-step explanation:
The probability of two independent events A, B (independent = events that do not depend on each other) is given by the product of the individual probabilities of A and B:
(1)
In this problem, the single event is "getting a 3" when extracting a random number between 1 and 10.
The total number of possible outcomes is
n = 10
While the number of succesfull outcomes (getting a 3) is only one:
So, the probability of drawing a 3 in 1 draw is
Then, we want to find the probability of getting three "3" in 3 consecutive generations. These events are independent events, so we can use rule (1) to find the total probability, and we get: