Answer:
10y + 29 ≤ -23
Step-by-step explanation:
subtract 29 from each side to get:
10y ≤ -52
y ≤ -5.2
The correct format of the question is
At the end of 2006, the population of Riverside was 400 people. The population for this small town can be modeled by the equation below, where t represents the number of years since the end of 2006 and P represents the number of people. 
Based on this model, approximately what was the increase in the population of Riverside at the end of 2009 compared to the end of 2006?
(A) 291
(B) 691
(C) 1040
(D) 1440
Answer:
The increase in the population at the end of 2009 is 291 people
Step-by-step explanation:
We are given the equation as
where
P = No of People
t= No of Years
it is given that in the year 2006 the population is 400
this will only happen when we take t= 0
so for
Year value of t
2006- t = 0
2007- t = 1
2008- t = 2
2009 t = 3
No of people in 2009 will be
= 400*1.728
P = 691.2
Since the equation represents no of people so it can't be in decimals, Therefore the population will be 691
Increase = P(2009) - P(2006)
= 691 - 400
= 291
The increase in the population at the end of 2009 is 291 people.
Answer:
0.25x + y = 12
Step-by-step explanation:
Given
Kiran is spending $12 on games
it means that he can spend total of $12 on rides and games
number of games is represented by x
cost of 1 game = $0.25
cost of x games = $0.25*x = $0.25x
number of rides is represented by y
cost of 1 rides = $1
cost of x rides = $1*y = $y
Total cost for x games and y rides =cost of x games + cost of y rides
Total cost for x games and y rides = $0.25x + $y
given that Kiran is spending $12 on games
Total cost for x games and y rides will be $12
thus,
$12 = $0.25x + $y
removing dollar sign for equation formation
0.25x + y = 12
given above is the equation to represent the relationship between the dollar
amount Kiran is spending and the number of games, x, and the number of
rides, y.
The answer is 60% but you can make it higher if your teacher let's you correct it.
Answer:
(x-1)^5 (x+1)
Step-by-step explanation:
2 (x-1)^5 + (x-1)^6
Factor out (x-1)^5
2 (x-1)^5 + (x-1)^5 (x-1)
(x-1)^5( 2 + x-1)
Combine like terms
(x-1)^5 (x+1)
