In standard form, slope is always the negative of the x coefficient over the y coefficient.
If you dont want to have that memorized, you can use algebra to get the equation of the line into slope-intercept form (y=mx+b)
Set it equal to y
2x - 5y = 6
2x = 5y + 6
2x - 6 = 5y
(2/5)x - 6/5 = y
Now it is in slope intercept form. In slope intercept form, the coefficient multiplying with x is the slope of the line. Therefore, the slope equals 2/5.
It wants it to be in slope-intercept form.
y=mx+b
We have to first find the slope and plug it into point-slope form.
y-y1=m(x-x1)
Find the slope of the second line. (I did this one first on accident)
Rise/run= 3/1= 3 The slope is 3. Plug that in along with the point (0,3)
y-3=3(x-0)
y-3=3x
Add 3 to the other side.
y= 3x +3 <- <em>for the second line</em><em>
</em>
Now, the second.
rise/run= 1/2= .5 Use point (6,0)
y-0=.5(x-6)
y= .5x-3
y=.5x-3 <- for the first line
I hope this helps!
~kaiker
Lol I actually laughed at this silly much ?
Answer:
D) 81x²y¹⁰
Step-by-step explanation:
(9xy⁵)²
Because all of 9xy⁵ are in the parentheses, each component is raised to the 2nd degree.
(9)² = 81
(x)² = x²
(y⁵)² = y¹⁰ -- When you raise an exponent to another exponent, you multiply the exponents.
Now combine the components.
D) 81x²y¹⁰
We use the given data above to calculate the volume of gasoline that is being burned per minute by commercial airplanes.
Amount burned of 1 commercial airplane = <span>3.9 × 10³ ml of gasoline per second
Number of airplanes = </span><span>5.1 × 10³ airplanes
We calculate as follows:
</span> 3.9 × 10³ ml of gasoline per second / 1 airplane (5.1 × 10³ airplanes)(60 second / 1 min ) = <span>1.2 x 10^9 mL / min</span>
