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34kurt
3 years ago
6

Help with the following complete the square equation...

Mathematics
1 answer:
Aneli [31]3 years ago
4 0
<h3>Answer:  D) Add 64 to both sides</h3>

Why do this?

Because we want to be able to factor the left hand side into the form p^2, where p is some algebraic expression. This will help us ultimately solve for x.

Currently, the left hand side is x^2+16x which does factor to x(x+16), but that isn't in the form p^2. We want something like (x+1)^2 or (x+2)^2. The general form is (x+k)^2 where k is some fixed constant.

Let's expand out (x+k)^2 using the FOIL rule and we get x^2+2kx+k^2

The x coefficient is 2k. If we cut that in half, we get k. Squaring that result leads to k^2.

So we have this order: 2k cuts in half to k then square it to get k^2

For x^2+16x, we have the x coefficient as 16. That cuts in half to 8, then that squares to 64. We add 64 to both sides

Note how

x^2+16x = 9

x^2 + 16x + 64 = 9+64

(x+8)^2 = 73

From here, we apply the square root to both sides and then subtract 8 from both sides to fully isolate x. You would get two different solutions.

-------------

I recommend you use the FOIL rule to confirm that (x+8)^2 expands out to x^2+16x+64, to help check your work.

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Endpoint: (1,7), midpoint: (-10,10)
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The answer is (-21, 13) for The second endpoint.  

Let's start by calling the known endpoint L and the unknown K. We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.

(Kx + Lx)/2 = Mx

(Kx + 1)/2 = -10

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And now we do the same thing for y values

(Ky + Ly)/2 = My

(Ky + 7)/2 = 10

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Ky = 13

This gives us the final point of (-21, 13)

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Is (-2,-6) a solution of y &lt; 7x + 8?​
mojhsa [17]

Answer:

not a solution

Step-by-step explanation:

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Answer:

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