Hello!
log₃(x) + log₃(x - 6) = log₃(7) <=>
<=> log₃(x * (x - 6)) = log₃(7) <=>
<=> log₃(x² - 6x) = log₃(7) <=>
<=> x² - 6x = 7 <=>
<=> x² - 6x - 7 = 0 <=>
<=> x² + x - 7x - 7 = 0 <=>
<=> x * (x + 1) - 7 * (x + 1) = 0 <=>
<=> (x + 1) * (x - 7) = 0 <=>
<=> x + 1 = 0 and x - 7 = 0 <=>
<=> x = -1 and x = 7, x ∈ { 6; +∞ } <=>
<=> x = 7
Good luck! :)
Answer:
so i dont have to answer why thank you
Step-by-step explanation:
Alright, so 2x+2=0 (with x being the number) is what I'm getting from this. Subtract 2 from both sides to get 2x=-2, and then divide by 2 to get x=-1
The four interior angles of a quadrilateral always add to 360<span>°, so the answer is 98</span>
Hello there,
So we are trying to find out is the angle ∠BAC in degrees.
So what we are going to do is. . .25- (2x-10)°.
That answer would be -2x+35.
So ∠BAC= -2x+35°.Hope this helps.
~Jurgen