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astraxan [27]
3 years ago
5

11. Ben is saving money to buy a TV that costs $495,

Mathematics
1 answer:
Nataliya [291]3 years ago
3 0
65x+75=495
-75 -75
65x=420
65/65 420/65
X=6.46
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4 0
2 years ago
To get from his house to the lecture hall at school, Lin walked west 651 feet. After class, he walked northeast 910 feet to the
Ahat [919]

The general direction that Lin walked from the gym to his house is; B: Lin walked southwest, creating an obtuse triangle.

<h3>How to interpret distance bearing?</h3>

We are given;

Distance between the lecture hall and gym = 910 feet.

Distance between the gym and Lin apostrophe's house = 615 feet.

Distance between the lecture hall and Lin apostrophe's house = 651 feet.

Now, since this 3 distances form a triangle and the 3 distances are unequal, then we can call it an obtuse triangle since he walked west and then walked northwest.

Now, since he walked back to his house from the gym, we can say that he walked southwest if we picture the bearing of his first two directions.

Read more about Distance Bearing at; brainly.com/question/22719608

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4 0
2 years ago
Giving brainliest!!!! please help!!
liberstina [14]

Answer:

{4, 5 }

Step-by-step explanation:

Solve the inequality

n + 1 > 4 ( subtract 1 from both sides )

n > 3

The set of values that make the inequality true is { 4, 5 }

8 0
2 years ago
Pls help its due today if it's correct I'll make you Brainliest!!!!​
oee [108]

Answer:

b or c

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Questions Below. Would Appreciate Help!
kherson [118]

Answer:

The function that could be the function described is;

f(x) = -10 \cdot cos \left (\dfrac{2 \cdot \pi }{3} \cdot x \right ) + 10

Step-by-step explanation:

The given parameters of the cosine function are;

The period of the cosine function = 3

The maximum value of the cosine function = 20

The minimum value of the cosine function = 0

The general form of the cosine function is presented as follows;

y = A·cos(ω·x - ∅) + k

Where;

\left | A \right | = The amplitude = Constant

The period, T = 2·π/ω

The phase shift, = ∅/ω

k = The vertical translation = Constant

Therefore, by comparison, we have;

T = 3 = 2·π/ω

∴ ω = 2·π/3

The range of value of the cosine of an angle are;

-1 ≤ cos(θ) ≤ 1

Therefore, when A = 10, cos(ω·x - ∅) = 1 (maximum value of cos(θ)) and k = 10, we have;

y = A × cos(ω·x - ∅) + k

y = 10 × 1 + 10 = 20 = The maximum value of the function

Similarly, when A = 10, cos(ω·x - ∅) = -1 (minimum value of cos(θ)) and k = 10, we get;

y = 10 × -1 + 10 = 0 = The minimum value of the function

Given that the function is a reflection of the parent function, we can have;

A = -10, cos(ω·x - ∅) = -1 (minimum value of cos(θ)) and k = 10, to get;

y = -10 × -1 + 10 = 20 = The maximum value of the function

Similarly, for cos(ω·x - ∅) = 1 we get;

y = -10 × 1 + 10 = 0 = The minimum value of the function

Therefore, the likely values of the function are therefore;

A = -10, k = 10

The function is therefore presented as follows;

y = -10 × cos(2·π/3·x) + 10

8 0
2 years ago
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