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2 years ago

NEWSPAPERS Tamika delivered 50- newspapers last summer. Write 50% as a product of the same factor. Then find the value.

Mathematics

1 answer:

Annette [7]2 years ago

5 0

This question was not written correctly

Complete Question

NEWSPAPERS Tamika delivered 50² newspapers last summer. Write 50² as a product of the same factor. Then find the value.

Answer:

The value is 2500

Step-by-step explanation:

We are told in the above question that:

Tamika delivered 50² newspapers last summer.

Writing 50² as a product is given as:

50 × 50

Hence, the value of 50 × 50

= 2500.

Therefore, the value is 2500

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2 years ago

Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!

yan [13]

Answer:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}$

Step-by-step explanation:

You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

$cos(2\theta)=1-2sin^2(\theta)$

so we will make that replacement, getting everything in terms of sin:

$sin(\theta)+1=1-2sin^2(\theta)$

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

$2sin^2(\theta)+sin(\theta)=0$

We can factor out the sin(theta), since it's common in both terms:

$sin(\theta)(2sin(\theta)+1)=0$

Because of the Zero Product Property, either

$sin(\theta)=0$ or

$2sin(\theta)+1=0$

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}$

The next equation needs to first be solved for sin(theta):

$2sin(\theta)+1=0$ so

$2sin(\theta)=-1$ and

$sin(\theta)=-\frac{1}{2}$

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:

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2 years ago

Find f if f(x)=23; 23= x²+7

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3 years ago

1. tan a = cot(a + 10°)

Temka [501]

Answer:

$a=40+90n$

Step-by-step explanation:

Use a cofunction identity on the right hand side or left hand side...

So $\tan(a)=\cot(90-a)$ .

We have the equation:

$\tan(a)=\cot(a+10)$

Make the above replacement:

$\cot(90-a)=\cot(a+10)$

Since cotangent has period 180 degrees, we can also write this as:

$\cot(90-a+180n)=\cot(a+10)$

So solving the following will give us a set of solutions for $a$ :

$90-a+180n=a+10$

Add $a$ on both sides:

$90+180n=2a+10$

Subtract 10 on both sides:

$80+180n=2a$

Divide both sides by 2:

$40+90n=a$

Symmetric property:

$a=40+90n$

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2 years ago

NEWSPAPERS Tamika delivered 50- newspapers last summer. Write 50% as a product of the same factor. Then find the value.​

NEWSPAPERS Tamika delivered 50- newspapers last summer. Write 50% as a product of the same factor. Then find the value.