Smart Watches are taking over normal watches. They are getting WAYYY cheaper. There is one for about $14
Answer:
dog
Explanation:
Given the code :
>>> A = [21, 'dog', 'red']
>>> B = [35, 'cat', 'blue')
>>> C = [12, 'fish', 'green']
>>> E = [A, B, C]
the value of E[0][1]
Here, square boxes is used to select the value at E[0] ; the output is then used to select the value at index 1 of E[0] output.
Note that, indexing starts at 0; hence first list element is 0, then, 1, 2, and so on.
At
E[0] ; list E, index 0 (first element in the list) , gives an output A
Then, A[1] ; list A, index 1 (second element in the list) gives 'dog'
Answer:
the output of the above program is
2 3
3 5
8
Explanation:
It seems the program is trying to pair two numbers into one and leaving the unpaired number (in a case of odd number of numbers) as a separate output.
This is why numbers 2 and 3 form 23, numbers 3 and 5 form 35 and 8 is another output of the program.
For( count = 50; count > 0; count-- )
System.out.println( count );
