Ask question

Ask question

All categories

2 years ago

9

Given 100 grams of bacteria that decreases at the rate of 1/2 per year. What would be an appropriate range after 4 years

1 answer:

Brilliant_brown [7]2 years ago

8 0

Answer: B 0

Step-by-step explanation:

You might be interested in

Use the drop-down menus to select answers. Use the fraction bars and the expression provided to answer the questions. 3 ÷ 2 5 Ho

Dima020 [189]

Answer: it would be 7.5

8 0

2 years ago

Read 2 more answers

Anastasia is grocery shopping with her father and wonders how much shopping is left to do. "We already have 6 0 % 60%60, percent

Molodets [167]

If there are 12 items adding up to 60%, we want to know how many items more it will take to equal 100% So set up this equation 12/x = .6 then solve for x. x=12/.6 x = 20 now that we know the total you can subtract 12 from 20 and get 8, that is the number of items left on the list.

8 0

3 years ago

Read 2 more answers

Can you guys check my work pls?

alex41 [277]

Hey number 8. Be super careful, less than always look at that it should be 5n-3

3 0

2 years ago

Hii, can someone please help? I'm giving BRAINLIEST

Nookie1986 [14]

Answer:

It would Be C I hoped this helped

5 0

2 years ago

Read 2 more answers

wind resistance varies jointly as an objects surface area and velocity. if an object traveling at 55 miles per hour with a surfa

nikdorinn [45]

Answer:

25 miles per hour

Step-by-step explanation:

Given

$W = Wind\ resistance$

$A = Surface\ Area$

$V = Velocity$

The joint variation can be represented as:

$W\ \alpha\ A*V$

Where:

$V = 55; A = 20; W = 220$

Required

Find V, when: $A = 55; W = 275$

We have:

$W\ \alpha\ A*V$

Express as an equation

$W= k *A*V$

Where k is the constant of variation

Make k the subject

$k = \frac{W}{A*V}$

When: $V = 55; A = 20; W = 220$

We have:

$k = \frac{220}{20 *55 }$

$k = \frac{220}{1100}$

$k = 0.2$

When: $A = 55; W = 275$

We have:

$k = \frac{W}{A*V}$

Substitute: $A = 55; W = 275$ and $k = 0.2$

$0.2 = \frac{275}{55 * V}$

Make V the subject

$V= \frac{275}{55 * 0.2}$

$V= \frac{275}{11}$

$V= 25$

3 0

2 years ago